CODEWITHSUNDEEP
pythondjangofabric
Andrius
Andrius

Reputation: 21108

django deployment using fabric - TypeError: prepare_deployment() takes exactly 1 argument (0 given)

I'm using this guide: http://www.jeffknupp.com/blog/2012/02/09/starting-a-django-project-the-right-way/

To set up my django project. But I'm stuck at deployment part. I installed fabric using pip in my virtualenv. I created this file inside myproject directory:

from fabric.api import local

def prepare_deployment(branch_name):
    local('python manage.py test finance')
    local('git add -p && git commit')
    local('git checkout master && git merge ' + branchname)

from fabric.api import lcd

def deploy():
    with lcd('home/andrius/djcode/myproject/'):
        local('git pull /home/andrius/djcode/dev/')
        local('python manage.py migrate finance')
        local('python manage.py test finance')
        local('/my/command/to/restart/webserver')

But when I enter this command (as shown in a guide):

fab prepare_deployment

I get this error:

Traceback (most recent call last):
  File "/home/andrius/env/local/lib/python2.7/site-packages/fabric/main.py", line 732, in main
    *args, **kwargs
  File "/home/andrius/env/local/lib/python2.7/site-packages/fabric/tasks.py", line 345, in execute
    results['<local-only>'] = task.run(*args, **new_kwargs)
  File "/home/andrius/env/local/lib/python2.7/site-packages/fabric/tasks.py", line 121, in run
    return self.wrapped(*args, **kwargs)
TypeError: prepare_deployment() takes exactly 1 argument (0 given)

So even though it didn't specify in guide to enter argument, I suppose it requires my branch name. So entered this:

fab prepare_deployment v0.1

(v0.1 is my branch name) So now I got this error:

Warning: Command(s) not found:
    v0.1

Available commands:
    deploy
    prepare_deployment

Also I noticed in a guide for file fabfile.py in function prepare_deployment, input is written as 'branch_name' and inside function there is argument 'branchname'. So I thought it should be the same and renamed 'branchname' to 'branch_name', but still getting the same error.

So I think I'm doing something wrong here. What could be the problem?

Update: I tried to call function inside fabfile.py with:

prepare_deployment("v0.1")

Output was this:

[localhost] local: python manage.py test finance
Creating test database for alias 'default'...
Got an error creating the test database: permission denied to create database

Type 'yes' if you would like to try deleting the test database 'test_finance', or 'no' to cancel: yes
Destroying old test database 'default'...
Got an error recreating the test database: database "test_finance" does not exist


Fatal error: local() encountered an error (return code 2) while executing 'python manage.py test finance'

Aborting.

I think I should also mention that my app name is 'finance' as database name 'finance'. Maybe those are conflicting?

Upvotes: 2

Views: 1393

Answers (2)

aychedee
aychedee

Reputation: 25569

fabric uses a specific syntax for passing arguments to tasks from the command line. From a bash shell you would need to use

fab prepare_deployment:v0.1

You can read about it in the fabric documentation on per task arguments.

If you ever actually need to use brackets in a bash command you would need to escape them.

Upvotes: 5

Ian Atkin
Ian Atkin

Reputation: 6346

As you stated, this function should look like this...

def prepare_deployment(branch_name):
    local('python manage.py test finance')
    local('git add -p && git commit')
    local('git checkout master && git merge ' + branch_name)

Then you simply call...

fab prepare_deployment("v0.1")

Upvotes: 0

Related Questions