CODEWITHSUNDEEP
php
user1919
user1919

Reputation: 3938

Echo image with php

I am trying to do something really simple with php but I can not find where I have the mistake! So, I want to echo an image like this (part of the code):

    $file_path[0] = "/Applications/MAMP/htdocs/php_test/image_archive/".$last_file[0];
    echo $file_path[0];
    echo "<br>";
    echo "<img src=\".$file_path[0].\" alt=\"error\">";

I must have some kind of error when I echo the img tag but I can not find it. Any help would be appreciated.

  <div class="content">
   <h1> Map</h1>
  <?php

  include '/Applications/MAMP/htdocs/php_test/web_application_functions/last_file.php'; 
  $last_file = last_file(); 

 $file_path[0] = "/Applications/MAMP/htdocs/php_test/image_archive/".$last_file[0];
echo $file_path[0];
echo "<br>";
echo '<img src="' . $file_path[0] . '" alt="error">';
?>
<!-- end .content --></div>

Upvotes: 0

Views: 66633

Answers (2)

Popnoodles
Popnoodles

Reputation: 28409

echo "<img src=\".$file_path[0].\" alt=\"error\">";

is wrong

echo "<img src=\"".$file_path[0]."\" alt=\"error\">";

is what you think you're doing

It's useful to use single quotes so you don't make this mistake

echo '<img src="' . $file_path[0] . '" alt="error">';

Secondly

/Applications/MAMP/htdocs/php_test/image_archive/ looks like a path not a directory

Perhaps you mean 

$file_path[0] = "/php_test/image_archive/".$last_file[0];

or

$file_path[0] = "image_archive/".$last_file[0];

Upvotes: 3

PassKit
PassKit

Reputation: 12581

You should use a path either relative to the server root, or the current file.

echo "<img src='/php_test/image_archive/" . $last_file[0] . "' alt='error'>";

Upvotes: 5

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