CODEWITHSUNDEEP
regexgo
djhworld
djhworld

Reputation: 6776

Regular expression doesn't work in Go

forgive me for being a regex amateur but I'm really confused as to why this doesn't piece of code doesn't work in Go 

package main

import (
    "fmt"
    "regexp"
)

func main() {
    var a string = "parameter=0xFF"
    var regex string = "^.+=\b0x[A-F][A-F]\b$"
    result,err := regexp.MatchString(regex, a)
    fmt.Println(result, err)
}
// output: false <nil>

This seems to work OK in python

import re

p = re.compile(r"^.+=\b0x[A-F][A-F]\b$")
m = p.match("parameter=0xFF")
if m is not None:
    print m.group()

// output: parameter=0xFF

All I want to do is match whether the input is in the format <anything>=0x[A-F][A-F]

Any help would be appreciated

Upvotes: 3

Views: 2376

Answers (2)

Denys S&#233;guret
Denys S&#233;guret

Reputation: 382122

You must escape the \ in interpreted literal strings :

var regex string = "^.+=\\b0x[A-F][A-F]\\b$"

But in fact the \b (word boundaries) appear to be useless in your expression.

It works without them :

var regex string = "^.+=0x[A-F][A-F]$"

Demonstration

Upvotes: 5

antoyo
antoyo

Reputation: 11913

Have you tried using raw string literal (with back quote instead of quote)? Like this:

var regex string = `^.+=\b0x[A-F][A-F]\b$`

Upvotes: 9

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