CODEWITHSUNDEEP
pythonfor-loop
André
André

Reputation: 25554

Python - How to check Booleans inside a for loop?

I'm without clues on how to do this. I've a list:

list_something = [5, 6, 8]

And I've a method is_valid()

def is_valid(number):
    return type(number) is int

How can I check at once if the 3 numbers are all Integers inside a for loop?

for item in list_something:

At the end of the for loop I need to have a variable called "all_list_something" and will have the value of True or False. If all the numbers in the list are Integer, the value is True. If only one fails to be Integer, the value will be false.

Any clues on the best way to achieve this?

Best Regards,

Upvotes: 2

Views: 205

Answers (3)

David Robinson
David Robinson

Reputation: 78590

You can use all and map:

all_list_something = all(map(is_valid, list_something))

Using itertools.imap would allow this to short-circuit (meaning that if the first element is invalid, it never checks the rest):

import itertools
all_list_something = all(itertools.imap(is_valid, list_something))

Upvotes: 8

Fredrick Brennan
Fredrick Brennan

Reputation: 7357

Since the question asks about how to do it in a for loop, I thought I'd include such an answer:

all_list_something = True
for item in list_something:
    if not is_valid(item):
       all_list_something = False
       break

But really, David or cmh's answer is the way to go.

Upvotes: 4

cmh
cmh

Reputation: 10927

A generator comprehension can improve readability over a map for some.

all_list_something = all(is_valid(x) for x in list_something)

Upvotes: 10

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