Reputation: 226
I am trying to replace the MessageParam within the XML tag with XXYY1...
The MessageParam has requested to travel <BR/>From <MessageParam name="0" desc="city code"/> to <MessageParam name="1" desc="city code"/> on <MessageParam name="2" desc="date"/> at <MessageParam name="3" desc="time"/>.
I expect the output to be
The MessageParam has requested to travel <BR/>From <XXYY1 name="0" desc="city code"/> to <XXYY2 name="1" desc="city code"/> on <XXYY3 name="2" desc="date"/> at <XXYY4 name="3" desc="time"/>.
Here is my code
private void ProcessString()
{
String text = "The Traveler has requested to travel <BR/>From <MessageParam name=\"0\" desc=\"city code\"/> to <MessageParam name=\"1\" desc=\"city code\"/> on <MessageParam name=\"2\" desc=\"date\"/> at <MessageParam name=\"3\" desc=\"time\"/>.";
int Counter = 0;
StringBuffer outString = new StringBuffer();
Pattern pattern = Pattern.compile("(<MessageParam.*?>)");
Matcher matcher = pattern.matcher(text);
while (matcher.find())
{
Counter++;
String sReplacer = new StringBuffer("XXYY").append(Counter).toString();
matcher.appendReplacement(outString, sReplacer);
}
matcher.appendTail(outString);
System.out.println(outString.toString());
}
The output i am getting is
The MessageParam has requested to travel <BR/> From XXYY1 to XXYY2 on XXYY3 at XXYY4.
I am pretty sure that my regex is not correct. since i am not good with regex i am not able to figure out whats going wrong.
Upvotes: 2
Views: 1638
Reputation: 7395
Simply use <MessageParam
as the regex and use <XXYY
as the replacement string portion.
Upvotes: 0
Reputation: 32787
The regex should be (?<=<)MessageParam
That would solve your problem
Upvotes: 2
Reputation: 308733
I wouldn't do such a thing with a regular expression.
I'd prefer to parse the source XML and map target values into an output XML using a template engine like Velocity.
My second choice would be an XSL-T transformation from one XML to another.
Upvotes: 3