Ritwik Dey
Ritwik Dey

Reputation: 609

connecting to a website from an android app

I am developing a simple android app that redirects to a particular website (for instance google) upon clicking on the 'start' button in my app home page. i have set the @id of my start button as 'bStart'. What should the coding be like in the method:

 start.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub
            ------------------
            ------------------
            ------------------
        }
});

Upvotes: 0

Views: 127

Answers (4)

NagarjunaReddy
NagarjunaReddy

Reputation: 8645

start.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View v) {
        // TODO Auto-generated method stub

       WebView webview = new WebView(classname.this);
       webview.setWebViewClient(new WebViewClient());       
       webview.setWebChromeClient(new WebChromeClient()); 
       webview.loadUrl("https://www.google.co.in/"); 

    }
}); 

Upvotes: 1

Varun Verma
Varun Verma

Reputation: 542

What I understand is you want to open a website on click of a button. Code to open a URL is:

Uri uri = Uri.parse("http://www.google.com");
Intent intent = new Intent(Intent.ACTION_VIEW, uri);
startActivity(intent);

Upvotes: 1

Nirav Tukadiya
Nirav Tukadiya

Reputation: 3417

Uri uri = Uri.parse("http://www.yourlinkhere.com");
    Intent intent = new Intent(Intent.ACTION_VIEW, uri);
    startActivity(intent);

here is the code you want.hope it will help.

Upvotes: 1

Gridtestmail
Gridtestmail

Reputation: 1479

    Uri uriUrl = Uri.parse(url);
    Intent launchBrowser = new Intent(Intent.ACTION_VIEW, uriUrl);
    startActivity(launchBrowser);

or

    Intent myWebLink = new Intent(android.content.Intent.ACTION_VIEW);
    myWebLink.setData(Uri.parse("http://www.google.co.uk"));
    startActivity(myWebLink);

Upvotes: 1

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