Reputation: 69
I have a table include some data like that. This is example for question/answer script. ID is auto increment and if PID=0 then it is question, when reply any question then PID is set to question's ID. There is no Subject for replies.
ID PID SUBJECT CONTENT DATE
1 0 First Question This is my first 09/01/2013
2 0 Second Question This is second 09/01/2013
3 1 Yes this is first 09/01/2013
4 2 I agree this is second 10/01/2013
5 0 Third Question This is third question 11/01/2013
6 1 Reply to first 11/01/2013
7 1 Another reply to first 12/01/2013
8 5 This is reply of 5th 13/01/2013
9 2 Last try for second 14/01/2013
My questions are,
How can I select questions with reply count?
Ex.
First Question (3)
Second Question (2)
Third Question (1)
How can I select today's answered questions or answers?
Ex. For 09/01/2013
First Question (2) ---> 1 question and 1 answer but 2 actions
Second Question (1) ---> just 1 question
Upvotes: 0
Views: 106
Reputation: 19882
Try join for first task
SELECT
q.id as ID,
q.pid as PID,
q.subject as SUBJECT,
COUNT(lq.id) as Total
FROM questions as q
LEFT JOIN questions as lq ON lq.pid = q.ID
WHERE q.PID = 0
GROUP BY q.id
OUTPUT
ID PID SUBJECT TOTAL
1 0 First Question 3
2 0 Second Question 2
5 0 Third Question 1
EDITS :
For second part. You should note that there can be many other ways for doing the same task.
SELECT
q.id as ID,
q.pid as PID,
q.subject as SUBJECT,
(COUNT(lq.id) - 1) as Total,
q.date
FROM questions as q
LEFT JOIN questions as lq ON lq.pid = q.ID OR lq.id = q.PID
WHERE q.date = DATE(NOW())
OUTPUT
ID PID SUBJECT TOTAL DATE
1 0 First Question 2 January, 09 2012 00:00:00+0000
2 0 Second Question 1 January, 09 2012 00:00:00+0000
Upvotes: 0
Reputation: 98388
Select the questions and join against the answers:
select q.id, q.subject, count(a.id)
from yourtable q
left join yourtable a on q.id=a.pid
where q.pid=0
group by q.id;
Upvotes: 1
Reputation: 13700
For question 1
select PID,count(*) from table
where pid<>0
group by PID
For question 2
select PID,count(*) from table
where pid<>0 and date=current_date()
group by PID
Upvotes: 0