Reputation: 5308
I am using PHP to connect with MongoDB. My code is as follows.
// connect
$m = new MongoClient($con_string); // connect to a remote host at a given port
$db = $m->main;
$customers = $db->customer->find();
i want to return $customers collection as json document to my HTML. How can i do this?
Upvotes: 12
Views: 17036
Reputation: 92
Other answers work, but it is good to know that the generated JSON will have the following form (in this example I use an hypothetical "name" field for your customers):
{
"5587d2c3cd8348455b26feab": {
"_id": {
"$id": "5587d2c3cd8348455b26feab"
},
"name": "Robert"
},
"5587d2c3cd8348455b26feac": {
"_id": {
"$id": "5587d2c3cd8348455b26feac"
},
"name": "John"
}
}
So in case you don't want the Object _id
to be the key of each of your result objects you can add a false
parameter to iterator_to_array
.
Your code would be:
echo json_encode(iterator_to_array($customers, false), true);
This creates the same result as
$result = Array();
foreach ($customers as $entry) {
array_push($result, $entry);
}
echo json_encode($result, true);
which is an array of JSON objects
[
{
"_id": {
"$id": "5587d2c3cd8348455b26feab"
},
"name": "Robert"
},
{
"_id": {
"$id": "5587d2c3cd8348455b26feac"
},
"name": "John"
}
]
Upvotes: 4
Reputation: 5308
This also will work. And you can customize your json as well.
$arr = array();
foreach($customers as $c)
{
$temp = array("name" => $c["name"], "phone" => $c["phone"],
"address" => $c["address"]);
array_push($arr, $temp);
}
echo json_encode($arr);
Upvotes: 8
Reputation: 43884
You can do this two ways:
echo json_encode(iterator_to_array($customers));
or you can manually scroll through it:
foreach($customers as $k => $row){
echo json_encode($row);
}
Each of MongoDBs objects should have their __toString()
methods correctly implemented to bring back the representation of the value.
Upvotes: 22