Reputation: 11756
I have a star rating system as defined like this:
<span class="rating_container">
<span class="star_container">
<a rel="nofollow" href="" class="star star_1" >1<span class="rating">Terrible</span></a>
<a rel="nofollow" href="" class="star star_2" >2<span class="rating">Bad</span></a>
<a rel="nofollow" href="" class="star star_3" >3<span class="rating">Bad</span></a>
<a rel="nofollow" href="" class="star star_4" >4<span class="rating">OK</span></a>
<a rel="nofollow" href="" class="star star_5" >5<span class="rating">OK</span></a>
<a rel="nofollow" href="" class="star star_6" >6<span class="rating">OK</span></a>
<a rel="nofollow" href="" class="star star_7" >7<span class="rating">Good</span></a>
<a rel="nofollow" href="" class="star star_8" >8<span class="rating">Good</span></a>
<a rel="nofollow" href="" class="star star_9" >9<span class="rating">Excellent</span></a>
<a rel="nofollow" href="" class="star star_10" >10<span class="rating">Excellent</span></a>
</span>
</span>
Each individual star is colored when a mouseover happens. How can I simulate this with jquery? For instance I'd like to mouseover star 5. This is what I've tried:
$('.star.star_5').addClass('active');
What am I missing?
Upvotes: 2
Views: 11993
Reputation: 18078
Try :
$(".star_5").trigger('mouseover');
This will trigger the mouseover action whatever it happens to be, rather than emulating it, offering a measure of future-proofing against changes to the mouseover handler.
Upvotes: 5
Reputation: 4519
In case you really want to simulate an event: You can trigger JavaScript events using parameterless forms of the corresponding jQuery functions. For example:
$('.star.star_5').mouseover();
Upvotes: 0
Reputation: 46657
In CSS (which is what jQuery selectors are based on), .class1 .class2
means "an element with class2 that has an ancestor with class1". This is not what you want. You want .class1.class2
which means "an element with both class1 and class2":
$('.star.star_5').addClass('active');
Upvotes: 0
Reputation: 79850
I think what you need is
$('.star.star_5').addClass('active');
Note the no-space between .star
and .star_5
and the _
in star_5
. (Thanks @wirey)
Upvotes: 2