CODEWITHSUNDEEP
javafx
user1809940
user1809940

Reputation:

Play Video in Javafx (Ubuntu)

my code id

public class Video1 extends Application {

private static String arg1;

@Override public void start(Stage stage) {
    stage.setTitle("Media Player");

// Create media player

    Media media = new Media("/home/ubuntu/NetBeansProjects/VideoPaly/src/videopaly/vid.flv");

    javafx.scene.media.MediaPlayer mediaPlayer = new javafx.scene.media.MediaPlayer(media);
    mediaPlayer.setAutoPlay(true);
    mediaPlayer.setCycleCount(javafx.scene.media.MediaPlayer.INDEFINITE);

// Print track and metadata information
    media.getTracks().addListener(new ListChangeListener<Track>() {
public void onChanged(Change<? extends Track> change) {
            System.out.println("Track> "+change.getList());
        }
    });
    media.getMetadata().addListener(new MapChangeListener<String,Object>() {
public void onChanged(MapChangeListener.Change<? extends String, ? extends Object>   change) {
            System.out.println("Metadata> "+change.getKey()+" -> "+change.getValueAdded());
        }
    });

 // Add media display node to the scene graph
    MediaView mediaView = new MediaView(mediaPlayer);
    Group root = new Group();
    Scene scene = new Scene(root,800,600);
    root.getChildren().add(mediaView);
    stage.setScene(scene);
    stage.show();
}

public static void main(String[] args) {
if (args.length > 0) {
        arg1 = args[0];
    }
    Application.launch(args);
}
}

I want to Play Video From Resource of Ubuntu when i run above code it give error like java.lang.IllegalArgumentException: uri.getScheme() == null! at line 

Media media = new Media("/home/ubuntu/NetBeansProjects/VideoPaly/src/videopaly/vid.flv");

any idea about that?

Upvotes: 1

Views: 963

Answers (1)

invariant
invariant

Reputation: 8900

From JavafX2 Media Class constructor doc :

Constructs a Media instance. This is the only way to specify the media source. The source must represent a valid URI and is immutable. Only HTTP, FILE, and JAR URLs are supported. If the provided URL is invalid then an exception will be thrown

Throws: java.lang.IllegalArgumentException - if the URI string does not conform to RFC-2396 or, if appropriate, the Jar URL specification, or is in a non-compliant form which cannot be modified to a compliant form.

so your source uri should be like this :

file://path to your media

Upvotes: 1

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