CODEWITHSUNDEEP
javaandroid
Asmi
Asmi

Reputation: 301

ReGex for the Postal code

I need to pull the 6 digit Postal code from the address.

"51 Bras Basah Road #01-01 Manulife Centre Singapore 189554"

The postal code is always 6 digit, but not surely in the last of the address.

Please help me giving a proper "java" regex to get postal code from above address.

Asmi

Upvotes: 0

Views: 4295

Answers (3)

Dilum Ranatunga
Dilum Ranatunga

Reputation: 13374

Here's a regex that will find the last six digit number:

((\d{6}.*)*\s)?(\d{6})([^\d].*)?$

Of course, you will need to escape the string when compiling the pattern:

Pattern postal_code_group3 = Pattern.compile("((\\d{6}.*)*\\s)?(\\d{6})([^\\d].*)?$");

You can get the postal code from group 3 of any match.

Note that group 2 forces a whitespace before the postal code, unless the string starts with the postal code.

Group 4 takes care of anything after the postal code, and also prevents a trailing 7-or-more digit number from being matched as the postal code.

Upvotes: 0

Jannik Jochem
Jannik Jochem

Reputation: 1546

If you can be sure that the postal code is the only 6-digit number in your input, you should be able to get away with: 

Pattern zipPattern = Pattern.compile("(\\d{6})");
Matcher zipMatcher = zipPattern.matcher("51 Bras Basah Road #01-01 Manulife Centre Singapore 189554");
if (zipMatcher.find()) {
    String zip = zipMatcher.group(1);
}

Also see the API documentation of java.util.regex.Pattern.

Upvotes: 6

rkb
rkb

Reputation: 16

Here is simple regexp

(.*)((\d){6})$

First group is "51 Bras Basah Road #01-01 Manulife Centre Singapore" 2nd group is postal code (6digits)

Upvotes: 0

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