Reputation: 23
I have a timer function and I want to clear the timeouts or reset the function, cause every time I execute it, a new timeouts are created, so I recieve several counts. My idea is to reset the count every time I execute the function. I only want a 1 instance of timer and get the correct count. If if execute several times the function I want to restart to 0.
Here is my code:
var timeouts = new Array();
var timer = null;
io.sockets.on('connection', function (client)
{
client.on("start", function (){
console.log('Someone has pressed Start button',new Date().getTime());
//try to kill all timeouts
for (var timeout in timeouts) {
clearTimeout(timeout);
};
if(this.timer == null) {
this.timer = new timer(1000, function (data) {
io.sockets.emit('timeupdate', data);
})
}else {
this.timer = null;
});
});
function timer(delay, callback)
{
// self-reference
var self = this;
if (!(this instanceof timer)) {
return new timer();
}
// attributes
var counter = 0;
var start = new Date().getTime();
/**
* Delayed running of the callback.
*/
function delayed()
{
console.log(counter);
callback(counter);
counter ++;
var diff = (new Date().getTime() - start) - counter * delay;
var timeOut = setTimeout(delayed, delay - diff);
timeouts.push(timeOut);
}
// start timer
delayed();
var timeout = setTimeout(delayed, delay);
timeouts.push(timeout);
}
Thank you in advance.
Upvotes: 3
Views: 2513
Reputation: 4519
Using clearTimeout()
is the correct way. The problem is your for
-loop. This might look like a classic foreach
-loop, but it is not. You have to do:
for (var i=0; i< timeouts.length; i++) {
clearTimeout(timeouts[i]);
}
Alternatively, also I don't like this personally:
for (var i in timeouts) {
clearTimeout(timeouts[i]); // note how the array is indexed using var i
}
This is a common JavaScript pitfall - the for (x in y)
-loop actually iterates over the array's indices, not the values. It can also iterate over an object's properties. Try it out:
var a = [3, 2, 5, 8];
for (var i in a) {
console.log(i);
console.log(a[i]);
}
var o = { test: 'hello', number: 1234 };
for (var x in o)
console.log(x);
Upvotes: 2