Reputation: 369
I have a Interface that has 4 buttons across the top of the screen, and below that I have QFrame. I want to change the layout in the QFrame based on what button is pressed. For instance, if Button_1 is pressed show a TextEdit Widget, if Button_2 is pressed show a ListViewWidget.
Does anyone have any idea on how this can be done? Thank You Very Much!
Upvotes: 4
Views: 3591
Reputation: 36715
Use a QStackedLayout
to store your widgets. Then you can change to the one with setCurrentIndex
. Alternatively, you can use a QStackedWidget
in place of your QFrame
.
A simple example:
import sys
from PySide import QtGui
class Window(QtGui.QWidget):
def __init__(self, parent=None):
super(Window, self).__init__(parent)
self.textEdit = QtGui.QTextEdit('Text Edit')
self.listWidget = QtGui.QListWidget()
self.listWidget.addItem('List Widget')
self.label = QtGui.QLabel('Label')
self.stackedLayout = QtGui.QStackedLayout()
self.stackedLayout.addWidget(self.textEdit)
self.stackedLayout.addWidget(self.listWidget)
self.stackedLayout.addWidget(self.label)
self.frame = QtGui.QFrame()
self.frame.setLayout(self.stackedLayout)
self.button1 = QtGui.QPushButton('Text Edit')
self.button1.clicked.connect(lambda: self.stackedLayout.setCurrentIndex(0))
self.button2 = QtGui.QPushButton('List Widget')
self.button2.clicked.connect(lambda: self.stackedLayout.setCurrentIndex(1))
self.button3 = QtGui.QPushButton('Label')
self.button3.clicked.connect(lambda: self.stackedLayout.setCurrentIndex(2))
buttonLayout = QtGui.QHBoxLayout()
buttonLayout.addWidget(self.button1)
buttonLayout.addWidget(self.button2)
buttonLayout.addWidget(self.button3)
layout = QtGui.QVBoxLayout(self)
layout.addLayout(buttonLayout)
layout.addWidget(self.frame)
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
w = Window()
w.show()
sys.exit(app.exec_())
Upvotes: 7
Reputation: 1188
Something like...
myframe.layout().removeWidget(mywidget)
mywidget = QTextEdit()
myframe.layout().addWidget(myWidget)
Upvotes: 2