user1877249
user1877249

Reputation: 3

Displaying two queries result i JSF

I'm trying to add some features to project which I find. There was query which selects specified results. Now I'm trying to get second query's results. Here's my code:

Car.java

@Entity
@NamedQueries({
@NamedQuery(name = "car.unsold", query = "Select c from Car c where c.sold = false"),
@NamedQuery(name="car.findByName", query=" SELECT C FROM Car c where c.make=?")
})
public class Car {  
private Long id;
private String make;
private String model;
//and all getters and setters   
 }

CarManager.java

@Stateless
public class CarManager {

@PersistenceContext
EntityManager em1;

@SuppressWarnings("unchecked")
public List<Car> getAvailableCars() {
    return em1.createNamedQuery("car.unsold").getResultList();
}

@SuppressWarnings("unchecked")
public List<Car> getCarsByName(String make){
    return em1.createNamedQuery("car.findByName").setParameter(1,   make).getResultList();
}}

CarBean.java

@SessionScoped
@Named("carBean")
public class CarFormBean implements Serializable {

private static final long serialVersionUID = 1L;

private Car car = new Car();
private ListDataModel<Car> cars = new ListDataModel<Car>();

private ListDataModel <Car> searchresult = new ListDataModel<Car>();

private String searchCar;
public String getSearchCar() {
    return searchCar;
}
public void setSearchCar(String searchCar) {
    this.searchCar = searchCar;
}
@Inject
private CarManager cm;  

public Car getCar() {
    return car;
}
public void setCar(Car car) {
    this.car = car;
}   

public ListDataModel<Car> getAvailableCars() {
    cars.setWrappedData(cm.getAvailableCars());
    return cars;
}

public ListDataModel<Car> getCarsByName(){
    searchresult.setWrappedData(cm.getCarsByName(searchCar));
    return searchresult;
}   
public String searchCar(){
    cm.getCarsByName(searchCar);
    return null;
    }   

My question is how to display the results of carByName query? Is the code above OK? Results of first query are printed by:

<rich:dataTable value="#{carBean.availableCars}" var="car" 

But how is it done? I can't see method called availableCars.

UPDATE Search.xhtml http://wklej.org/id/921560/ all.xhtml http://wklej.org/id/921561/

Upvotes: 0

Views: 973

Answers (1)

Elias Dorneles
Elias Dorneles

Reputation: 23916

In this case, the expression #{carBean.availableCars} does not refer to a method, but to a property of the bean carBean. So it evaluates to the method getAvailableCars() of the carBean. Take a loot at the Expression Language tag info page to learn more about this.

Note that it's not a good practice to call service methods on a getter (see this question). You'd be better with an initialization method annotated with @PostConstruct.

Also, you don't need a separate lists for the results. Just make an action method that fills the list of cars with the search results - say searchCars(), and make your search button to call it:

<h:commandButton value="Search" action="#{carBean.searchCars}" />

So, putting this together, this is what your bean code should look like:

@SessionScoped
@Named("carBean")
public class CarFormBean implements Serializable {
    private static final long serialVersionUID = 1L;        
    private Car car = new Car();

    // a list for storing the available cars and the search results
    private ListDataModel<Car> cars = new ListDataModel<Car>();        
    private String searchCar;

    @Inject
    private CarManager cm;

    // initialization method
    @PostConstruct
    public void init() {
        cars.setWrappedData(cm.getAvailableCars());
    }

    // action method
    public void searchCars() {
        cars.setWrappedData(cm.getCarsByName(searchCar));
    }

    // getters and setters
    public ListDataModel<Car> getAvailableCars() {
        return cars;
    }
    public Car getCar() {
        return car;
    }
    public void setCar(Car car) {
        this.car = car;
    }
    public String getSearchCar() {
        return searchCar;
    }
    public void setSearchCar(String searchCar) {
        this.searchCar = searchCar;
    }

Upvotes: 2

Related Questions