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c++templatesclang++
neuront
neuront

Reputation: 9612

clang++ - treat template class name as template in the class scope

It seems that clang++ (I tried clang 3.2) treats the name of a template class as a instantiated class, not a template for any occurence within the class scope. For example, the following codes

template <template <class> class T>
class A {};

template <typename T>
class B {
    A<B> member;
   // ^---- clang++ treats B as an instantiated class
         // but I want it to be a template here
         // this code could compile in g++
};

int main()
{
    B<int> b;
    return 0;
}

What should I do to compile that?

Upvotes: 4

Views: 397

Answers (2)

Potatoswatter
Potatoswatter

Reputation: 137780

C++03

Resolving B that way (called the injected-class-name, an implicitly-declared member of every class including template instantiations) is intended as a convenience. I've never seen it get in the way like that!

To work around, qualify the name by adding :: before it (and if necessary, the name of the namespace).

template <typename T>
class B {
    A< ::B> member; // whitespace required to prevent digraph; see comments
};

C++11

C++11 §14.6.1/1 specifies (emphasis mine)

Like normal (non-template) classes, class templates have an injected-class-name (Clause 9). The injected- class-name can be used as a template-name or a type-name. When it is used with a template-argument-list, as a template-argument for a template template-parameter, or as the final identifier in the elaborated-type- specifier of a friend class template declaration, it refers to the class template itself. Otherwise, it is equivalent to the template-name followed by the template-parameters of the class template enclosed in <>.

Therefore, if this problem occurs under C++11 it is a compiler bug. Workaround as above.

Note — for comparison, the corresponding paragraph in C++03 is

Like normal (non-template) classes, class templates have an injected-class-name (clause 9). The injected- class-name can be used with or without a template-argument-list. When it is used without a template- argument-list, it is equivalent to the injected-class-name followed by the template-parameters of the class template enclosed in <>. When it is used with a template-argument-list, it refers to the specified class template specialization, which could be the current specialization or another specialization.

As you can see, there's already one special case allowing the identifier to be a class or template, depending on whether it occurs in a template-name. They just added a couple more cases.

Upvotes: 3

Johannes Schaub - litb
Johannes Schaub - litb

Reputation: 506905

This is nonconformant behavior as of C++11 because C++11 says that the injected class name (which is a name automatically declared within the class body) is a template when it is passed to a template template parameter. So your code should only fail in a C++03 implementation.

However there is no need to open a bug report about this now. I have already done it way back.

Upvotes: 1

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