CODEWITHSUNDEEP
racket
Brandon Mick
Brandon Mick

Reputation: 9

how do i write this operation in racket?

How would I formulate the following operation in racket?

(n^2 + 300) (13/n)?

I got the first part done-

(define (f n)
  ( +  ( * n n ) 300))

So If I type in (f 2) I would get 304.

But How do I add the second part of this equation (13/n)?

Upvotes: 0

Views: 122

Answers (2)

Leif Andersen
Leif Andersen

Reputation: 22332

If you want to just use direct multiplication, this works:

(define (f n)
  (* (+ (* n n) 300) (/ 13 n)))

If all you are going to do is square a number, then you could also do:

(define (f n)
  (* (+ (sqr n) 300) (/ 13 n)))

And finally, if you needed to raise n to some power, then you could also do:

(define (f n)
  (* (+ (expt n 2) 300) (/ 13 n)))

Upvotes: 4

C. K. Young
C. K. Young

Reputation: 223003

This is straightforward:

(define (f n)
  (* (+ (* n n) 300) (/ 13 n)))

Upvotes: 2

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