Reputation: 1536
i know there is another question on the same example, but for different issue.
This is the code example:
#include <stdio.h>
/* count digits, white space, others */
main()
{
int c, i, nwhite, nother;
int ndigit[10];
nwhite = nother = 0;
for (i = 0; i < 10; ++i)
ndigit[i] = 0;
while ((c = getchar()) != EOF)
if (c >= '0' && c <= '9')
++ndigit[c-'0'];
else if (c == ' ' || c == '\n' || c == '\t')
++nwhite;
else
++nother;
printf("digits =");
for (i = 0; i < 10; ++i)
printf(" %d", ndigit[i]);
printf(", white space = %d, other = %d\n", nwhite, nother);
}
After I run is and execute the program with , I get: digits = 0 0 0 0 0 0 0 0 0 0, white space = 0, other = 0. From Xcode...
But in the book they say "The output of this program on itself is: digits = 9 3 0 0 0 0 0 0 0 1, white space = 123, other = 345"
Can you tell me whats going on please..tnx.
Upvotes: 2
Views: 226
Reputation: 180987
From the book;
The output of this program on itself is
digits = 9 3 0 0 0 0 0 0 0 1, white space = 123, other = 345
Trying it with its own source as input;
> gcc test.c
> ./a.out < test.c
digits = 9 3 0 0 0 0 0 0 0 1, white space = 125, other = 345
Close, but I suspect the cut'n'paste from StackOverflow may account for the 2 extra white spaces :)
Upvotes: 1