CODEWITHSUNDEEP
php
chillers
chillers

Reputation: 1457

str_replace interference

I'm trying to convert a two letter language abbreviations to full words using str_replace. The problem I'm having is that they're affecting each other when echoed out.

$lang = str_replace("en", "English", $lang); 
$lang = str_replace("es", "Spanish", $lang);
$lang = str_replace("pt", "Portuguese", $lang); 
$lang = str_replace("fr", "French", $lang);
$lang = str_replace("de", "German", $lang);
$lang = str_replace("it", "Italian", $lang);
$lang = str_replace("pl", "Polish", $lang);
$lang = str_replace("ru", "Russian", $lang);
$lang = str_replace("sv", "Spanish (El Salvador)", $lang);
$lang = str_replace("ko", "Korean", $lang);
$lang = str_replace("zh", "Chinese", $lang);
$lang = str_replace("nl", "Dutch", $lang);

An example: when I echo out en, I get EnglIcelandich.

The list above is bigger but that is just a example. I have tried renaming the vars but with no luck.

Upvotes: 3

Views: 206

Answers (6)

Dawit
Dawit

Reputation: 11

$entries = array(
    "en" => "English",
    "es" => "Spanish",
    "pt" => "Portuguese",
    "fr" => "French",
    "de" => "German",
    "it" => "Italian",
    "pl" => "Polish",
    "ru" => "Russian",
    "sv" => "Spanish (El Salvador)",
    "ko" => "Korean",
    "zh" => "Chinese",
    "nl" => "Dutch"
);

Using str_replace:

for ( $i = 0 ;  $i < $entries['count']; $i++ ) {
    foreach($entries[$i] as $key => $entrie) {
        if ( is_string($key) ) {
        $result = str_replace('{'.$key.'}', $entrie[0], $result);
        }
    }

    $contact_data[] = $result;
}

Upvotes: -1

Brad Christie
Brad Christie

Reputation: 101614

Unless you expect things like ensppt as an original value, just use a mimic'd look-up table:

$lang_lookup = array(
  'en' => 'English',
  'es' => 'Spanish',
  'pt' => 'Portuguese',
  // ...
);
$lang = array_key_exists($lang, $lang_lookup) ? $lang_lookup[$lang] : 'Unknown';

Alternatively (but slower) you could copy one string to the other:

$lang_lookup = array(
  'en'=>'English',
  'es'=>'Spanish',
  'pt'=>'Portuguese', 
  'fr'=>'French',
  'de'=>'German',
  'it'=>'Italian',
  'pl'=>'Polish',
  'ru'=>'Russian',
  'sv'=>'Spanish (El Salvador)',
  'ko'=>'Korean',
  'zh'=>'Chinese',
  'nl'=>'Dutch'   
);
$lang = 'es stands for Spanish';

$output = '';
for ($i = 0; $i < strlen($lang); $i++){
  $l = substr($lang, $i, 2);
  if (array_key_exists($l, $lang_lookup)){
    $output .= $lang_lookup[$l];
    $i++;
  } else {
    $output .= $lang[$i];
  }
}
echo $output; // "Spanish stands for Spanish"

Upvotes: 0

Kyle
Kyle

Reputation: 1595

If $lang will always be a two character string, there is no need for search/replace at all, just use a lookup table like this:

$languages = array(
    'en'=>'English' 
    'es'=>'Spanish'
    'pt'=>'Portuguese' 
    'fr'=>'French'
    'de'=>'German'
    'it'=>'Italian'
    'pl'=>'Polish'
    'ru'=>'Russian'
    'sv'=>'Spanish (El Salvador)'
    'ko'=>'Korean'
    'zh'=>'Chinese'
    'nl'=>'Dutch'   
);
$lang = $languages[strtolower($lang)];

Upvotes: 1

Ry-
Ry-

Reputation: 225074

You can do them all at once using preg_replace_callback:

$map = array(
    'en' => 'English',
    ...
);

$lang = preg_replace_callback('/' . implode('|', array_keys($map)) . '/', function($match) use ($map) {
    return $map[$match[0]];
}, $lang);

Oh, and if any of your strings ever have any special characters in them, you'll need to map preg_quote to your array's keys and pass the delimiter as its second argument.

Upvotes: 2

Arnold Daniels
Arnold Daniels

Reputation: 16573

It's simple! Use strtr instead.

<?php
$replace = array(
    "en" => "English",
    "es" => "Spanish",
    "pt" => "Portuguese",
    "fr" => "French",
    "de" => "German",
    "it" => "Italian",
    "pl" => "Polish",
    "ru" => "Russian",
    "sv" => "Spanish (El Salvador)",
    "ko" => "Korean",
    "zh" => "Chinese",
    "nl" => "Dutch"
);

echo strtr("en it sv\n", $replace);

Upvotes: 7

Reactgular
Reactgular

Reputation: 54801

If there is only support to be one occurrence in the string, then just check which one exists first. Using an array as a lookup table.

$languages = array(
    'en'=>'English' 
    'es'=>'Spanish'
    'pt'=>'Portuguese' 
    'fr'=>'French'
    'de'=>'German'
    'it'=>'Italian'
    'pl'=>'Polish'
    'ru'=>'Russian'
    'sv'=>'Spanish (El Salvador)'
    'ko'=>'Korean'
    'zh'=>'Chinese'
    'nl'=>'Dutch'   
);

foreach($languages as $key=>$value)
{
    if(strpos($lang,$key) !== false)
    {
        $lang = str_replace($key,$value,$lang);
        break;
    }
}

Upvotes: 0

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