Reputation: 17005
I'm using time.h in C++ to measure the timing of a function.
clock_t t = clock();
someFunction();
printf("\nTime taken: %.4fs\n", (float)(clock() - t)/CLOCKS_PER_SEC);
however, I'm always getting the time taken as 0.0000. clock() and t when printed separately, have the same value. I would like to know if there is way to measure the time precisely (maybe in the order of nanoseconds) in C++ . I'm using VS2010.
Upvotes: 52
Views: 93406
Reputation: 2419
In C or C++ I usually do like below. If it still fails you may consider using rtdsc functions
struct timeval time;
gettimeofday(&time, NULL); // Start Time
long totalTime = (time.tv_sec * 1000) + (time.tv_usec / 1000);
//........ call your functions here
gettimeofday(&time, NULL); //END-TIME
totalTime = (((time.tv_sec * 1000) + (time.tv_usec / 1000)) - totalTime);
Upvotes: 2
Reputation: 11746
C++11 introduced the chrono API, you can use to get nanoseconds :
auto begin = std::chrono::high_resolution_clock::now();
// code to benchmark
auto end = std::chrono::high_resolution_clock::now();
std::cout << std::chrono::duration_cast<std::chrono::nanoseconds>(end-begin).count() << "ns" << std::endl;
For a more relevant value it is good to run the function several times and compute the average :
auto begin = std::chrono::high_resolution_clock::now();
uint32_t iterations = 10000;
for(uint32_t i = 0; i < iterations; ++i)
{
// code to benchmark
}
auto end = std::chrono::high_resolution_clock::now();
auto duration = std::chrono::duration_cast<std::chrono::nanoseconds>(end-begin).count();
std::cout << duration << "ns total, average : " << duration / iterations << "ns." << std::endl;
But remember the for
loop and assigning begin
and end
var use some CPU time too.
Upvotes: 107
Reputation: 1854
The following text, that i completely agree with, is quoted from Optimizing software in C++ (good reading for any C++ programmer) -
The time measurements may require a very high resolution if time intervals are short. In Windows, you can use the
GetTickCount
orQueryPerformanceCounter
functions for millisecond resolution. A much higher resolution can be obtained with the time stamp counter in the CPU, which counts at the CPU clock frequency.
There is a problem that "the clock frequency may vary dynamically and that measurements are unstable due to interrupts and task switches."
Upvotes: 6
Reputation: 35039
I usually use the QueryPerformanceCounter
function.
example:
LARGE_INTEGER frequency; // ticks per second
LARGE_INTEGER t1, t2; // ticks
double elapsedTime;
// get ticks per second
QueryPerformanceFrequency(&frequency);
// start timer
QueryPerformanceCounter(&t1);
// do something
...
// stop timer
QueryPerformanceCounter(&t2);
// compute and print the elapsed time in millisec
elapsedTime = (t2.QuadPart - t1.QuadPart) * 1000.0 / frequency.QuadPart;
Upvotes: 58