CODEWITHSUNDEEP
php
HellCoder
HellCoder

Reputation: 25

How to extract a float value from some number(php)

I have a number 1.5, 1.6666 or 1.777.

How can I extract those float values from the int part? Not just round but separate them in different vars.

Expected output is $var1 = 1 and $var2 = 0.5 for 1.5.

Upvotes: 0

Views: 94

Answers (5)

Glavić
Glavić

Reputation: 43572

You can do this with multiple ways. Lets say $v = 1.56; :

Example #1

$m = explode('.', $v);
$v1 = $m[0];
$v2 = '0.' . $m[1];
print_r("#1: \$v1 = $v1; \$v2 = $v2;\n");

Example #2

preg_match('~^(\d+)\.(\d+)$~', $v, $m);
$v1 = $m[1];
$v2 = '0.' . $m[2];
print_r("#2: \$v1 = $v1; \$v2 = $v2;\n");

Example #3

$v1 = substr($v, 0, strpos($v, '.'));
$v2 = '0.' . substr($v, strpos($v, '.') + 1);
print_r("#3: \$v1 = $v1; \$v2 = $v2;\n");

Example #4

$v1 = floor($v1);
$v2 = $v - $v1;
print_r("#4: \$v1 = $v1; \$v2 = $v2;\n");

All examples will output >

#1: $v1 = 1; $v2 = 0.56;
#2: $v1 = 1; $v2 = 0.56;
#3: $v1 = 1; $v2 = 0.56;
#4: $v1 = 1; $v2 = 0.56;

Watch out for the big float numbers. See BC Math functions for those.

Upvotes: 0

user1477388
user1477388

Reputation: 21440

You could also use:

$var = 1.5;
$arr = explode('.', $var);
$wholeNum = $arr[0];  // 1
$decimalNum = $arr[1];  // 5

Upvotes: 0

Marc Baumbach
Marc Baumbach

Reputation: 10473

First get the integer portion and then subtract it from the original.

$original = 1.6666;
$intPortion = intval($original);
$floatPortion = $original - $intPortion;

Upvotes: 1

Mike Brant
Mike Brant

Reputation: 71384

This is probably your best bet:

$float = 1.666;
$remainder = fmod($float, 1);
$integer = intval($float, 10);

Upvotes: 0

NeeL
NeeL

Reputation: 720

Interpret them as strings, and use preg_split

Upvotes: 0

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