CODEWITHSUNDEEP
javascriptjqueryajax
user1972864
user1972864

Reputation: 15

Remove a div after 5s

I have this AJAX form:

function form(){

        var icao = document.getElementById('icao').value;
        var name = document.getElementById('name').value;
        var weightempty = document.getElementById('weightempty').value;
        var weightfull = document.getElementById('weightfull').value;
        var cargofull = document.getElementById('cargofull').value;
        var cruisespeed = document.getElementById('cruisespeed').value;
        var range = document.getElementById('range').value;
        var price = document.getElementById('price').value;
        var firstclassseats = document.getElementById('firstclassseats').value;
        var businessclassseats = document.getElementById('businessclassseats').value;
        var economyclassseats = document.getElementById('economyclassseats').value;
        ajax.open("POST","new_aircraft_process.php",true);
        ajax.onreadystatechange=function(){
            if(ajax.readyState==4)
            {
            var respuesta=ajax.responseText;


            document.getElementById('result').innerHTML=ajax.responseText;
            $("#newaircraftdialog").dialog('close');


            refreshTable(function(){$("#loadingdialog").dialog('close');});
            }
        }
    ajax.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
    ajax.send("icao="+icao+"&name="+name+"&weightempty="+weightempty+"&weightfull="+weightfull+"&cargofull="+cargofull+"&cruisespeed="+cruisespeed+"&range="+range+"&price="+price+"&firstclassseats="+firstclassseats+"&businessclassseats="+businessclassseats+"&economyclassseats="+economyclassseats);
    $("#loadingdialog").dialog('open');
    }

I want is when the result is displayed (it is a text that says "Successful Form") in the result div is it visible only for 5 seconds and then disappears. I have found various ways, but do not want to delete the div. Because if I want to make the form another time the result of this will have to show again in the div and disappear after 5 seconds after.

Upvotes: 1

Views: 132

Answers (3)

Jai
Jai

Reputation: 74738

You can use delay()

$('divtoremove').delay(5000).fadeOut('fast');

Upvotes: 0

gpojd
gpojd

Reputation: 23065

You can hide the div and show it later when the form is resubmitted. 

ajax.onreadystatechange=function(){
    if(ajax.readyState==4)
    {
        var respuesta=ajax.responseText;


        var $result = $('#result');
        $result.html(ajax.responseText);
        $result.show();
        setTimeout(function() { $result.hide() }, 5000);
        $("#newaircraftdialog").dialog('close');


        refreshTable(function(){$("#loadingdialog").dialog('close');});
    }
}

You can also use detach and reattach it to the DOM later.

Upvotes: 0

David Harris
David Harris

Reputation: 2707

$('.myDiv').fadeIn(); // Show the div to start.
// All your other code here.
setTimeout(function() { $('.myDiv').fadeOut() }, 5000); // hide the div after we're done

Upvotes: 3

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