CODEWITHSUNDEEP
php
user1802209
user1802209

Reputation: 97

Put a line break before numeric character in string with php

I have strings like this:

123 qwerty 6 foo bar 55 bar

I need to make it like this

123 qwerty
6 foo bar
55 bar

How to make it?

UPD: I tried make it

$subject = "123 qwerty 6 foo 55 bar";
$pattern = '/[^0-9]/';
preg_match($pattern, substr($subject,3), $matches, PREG_OFFSET_CAPTURE);
echo "<pre>";
print_r($matches);

But it is no working for me.

Upvotes: 0

Views: 742

Answers (3)

Ayman Safadi
Ayman Safadi

Reputation: 11552

Try this:

$subject = '123 qwerty 6 foo 55 bar';
$pattern = '/ (?=[\d]+)/';
$replacement = "\n";

$result = preg_replace( $pattern, $replacement, $subject );

print_r( $result );

Produces:

123 qwerty
6 foo
55 bar

PHP Demo: http://codepad.org/MNLgaySd

The key is in the regular expression's "positive lookahead", (?=...)

Regex Demo: http://rubular.com/r/i4CdoEL9f4

Upvotes: 0

Adder
Adder

Reputation: 5868

Like this:

 $lineending= "\n";
 $parts= explode(' ',$string);
 $result= "";
 for($i=0; $i<count($parts);){
    $result .= $parts[$i];
    while(!is_numeric($parts[$i]) && $i<count($parts)){
        $result .= $parts[$i];
        $i+= 1;
    }
    $result .= $lineending; 
 }

;-)

Upvotes: 2

Oliver A.
Oliver A.

Reputation: 2900

you can use this:

$text = '123 qwerty 6 foo 55 bar baz';
$result = preg_replace('/([0-9]+[^0-9]+)/i', '$1\n', $text);

This looks for at least one number followed by at least one character which is NOT a number and adds a linebreak.

Read more abot:

Upvotes: 3

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