CODEWITHSUNDEEP
javaandroidhex
BBB
BBB

Reputation: 615

hex string to int conversion not working correctly

I have a hexidecimal number (a color) stored in a String as followed: "ff62e6b8". I need to convert this back to an integer so I can use it as a color value again. I have tried the following:

Int i = Integer.parseInt("ff62e6b8", 16);
Int i = Integer.valueOf("ff62e6b8", 16);
Int i = Integer.decode("ff62e6b8");

But all of these methods raise exceptions. Am I missing something here?

Upvotes: 2

Views: 194

Answers (4)

Pratik Sharma
Pratik Sharma

Reputation: 13415

Try with this :

int colorVal = Color.parseColor("#ff62e6b8");

Example :

myLayout.setBackgroundColor(Color.parseColor("#ff62e6b8"));

By this you will get colorVal = -10295624.

And if you want to generate hexColor code back from the colorVal then use this :

String hexColor = String.format("#%06X", (0xFFFFFF & colorVal));

By this you will get hexColor = #62E6B8.

Thanks.

Upvotes: 5

Adam Sznajder
Adam Sznajder

Reputation: 9206

FF62E6B8 is 4284671672 in decimal. It's simply to large to put it into int. In int you can store values which match the range <-2^31 - 1 ; 2^31 - 1>. Try to use long instead:

Long i = Long.parseInt("ff62e6b8", 16);
Long i = Long.valueOf("ff62e6b8", 16);
Long i = Long.decode("ff62e6b8");

Upvotes: 8

Paolo
Paolo

Reputation: 15827

the first one would be the good one

but ff62e6b8 exceeds the size of int (32 bit - signed), that's why an exception is raised.

Long l = Long.parseLong("ff62e6b8", 16);

should do the job

Upvotes: 1

Dororo
Dororo

Reputation: 3440

String hex = "1B";
int val = Integer.parseInt(hex, 16);

That is the correct conversion.

Upvotes: 0

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