CODEWITHSUNDEEP
rubyparallel-assignment
Alan Coromano
Alan Coromano

Reputation: 26008

Why does parallel assignment of a single empty array assign multiple nils?

I want to assign an empty array to multiple variables. Here is what I'm doing:

irb(main):015:0> a, b, c = []
=> []
irb(main):016:0> a
=> nil
irb(main):017:0> b
=> nil
irb(main):018:0> c
=> nil

It gives me nil. I wonder why? But if I did this:

irb(main):019:0> a, b, c = [], [], []
=> [[], [], []]
irb(main):020:0> a
=> []
irb(main):021:0> b
=> []
irb(main):022:0> c
=> []

then it works as I expect, but it's a little bit longer than the first one. What's wrong with the first example?

Upvotes: 3

Views: 561

Answers (4)

Andrew Haines
Andrew Haines

Reputation: 6644

Ruby destructures arrays when you do parallel assignment:

a, b, c = [:foo, :bar, :baz]
a # => :foo
b # => :bar
c # => :baz

If you give it an array with too few entries, it sets the remaining values to nil:

a, b, c = [:foo, :bar]
a # => :foo
b # => :bar
c # => nil

So your first example is just the natural extension of this - an empty array definitely has too few entries to assign any of the variables!

Upvotes: 0

Todd A. Jacobs
Todd A. Jacobs

Reputation: 84343

Parallel Assignment With Single Rvalue

If the assignment contains multiple lvalues and one rvalue, the Ruby attempts to expand the rvalue into an array as if you'd called #to_a on the rvalue. So, the problem with your example of a, b, c = [] is that it is semantically equivalent to:

a, b, c = nil.to_a

which would obviously assign nil to the first variable, and leave the others unassigned (which is also nil). In contrast, consider this:

a, b, c = 1
a
# => 1
b
# => nil
c
# => nil

The same principle is at work, but now you can see that the first lvalue does receive an assignment from the right-hand side; it just wasn't obvious when the assignment was nil.

Upvotes: 1

ZelluX
ZelluX

Reputation: 72605

I believe this example will help you understand the problem:

[1] pry(main)> a, b, c = [1,2]
=> [1, 2]
[2] pry(main)> a
=> 1
[3] pry(main)> b
=> 2
[4] pry(main)> c
=> nil

Now back to your problem, you are trying to assign the elements in an empty array to variables, as a result, the three variables all get nil value.

Upvotes: 2

zed_0xff
zed_0xff

Reputation: 33217

a = b = c = []

but note that all variables will be assigned the same array
so:

a = b = []
b << 1
p b        # [1]
p a        # [1]

Upvotes: 1

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