CODEWITHSUNDEEP
c#model-view-controllerview
kalki
kalki

Reputation: 13

Strongly typed views

is it possible to pass derived types where base types are expected to strongly typed views?

I.e

  1. Products/List
  2. News/List

where "list" view Inherits System.Web.Mvc.ViewPage<Model<BaseList>>

controller renders view i.e View("List", ProductsList)

edited

return View("List", new Model<ProductsList>());
Model<T> where T : IMyList 
ProductsList : BaseList
NewsList : BaseList
BaseList : IMyList

where ProductsList & NewsList : BaseList

compiles fine but get a runtime error about differing model types.

If this not possible what is the best way to accomplish this rather than creating n no of views ?

Upvotes: 0

Views: 128

Answers (2)

Boris Callens
Boris Callens

Reputation: 93317

I think (but am not sure) this has to do with Covariance.

How I'm doing this is create a strongly typed viewData like for example this:

public class YourViewData: System.Web.Mvc.ViewDataDictionary
{
    public IMyList TheList { get; set; }
}

You can then make a ViewPage that you call like

return View("List", new YourViewData(){TheList = new ProductList(){abunchOfItems});

Disclaimer: All freehand code

Upvotes: 1

erikkallen
erikkallen

Reputation: 34391

Your question is a little unclear, but I guess it has to do with you having an IList<Base> in your model and you want to pass an IList<Derived>. This is not possible, but in C#4 you can pass an IEnumerable<Derived> instead of an IEnumerable<Base>.

Upvotes: 0

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