Reputation: 1011
I have a few console command in Symfony2 and I need to execute one command from another command with some parameters.
After successfull execution of the second command I need to get the result (as an array for example), not the display output.
How can I do that?
Upvotes: 18
Views: 18858
Reputation: 11
As an update for Onema's answer, in Symfony 3.4.x (used by Drupal 8),
setAutoExit(false)
,int(0)
if successful.Here's the updated example that I'm using to script composer commands in php for a Drupal 8.8 project. This gets a list of all composer packages as json, then decodes that into a php object.
<?php
require __DIR__.'/vendor/autoload.php';
use Symfony\Component\Console\Output\BufferedOutput;
use Symfony\Component\Console\Input\ArrayInput;
use Composer\Console\Application;
$input = new ArrayInput([
'command' => 'show',
'--format'=>'json',
]);
$output = new BufferedOutput();
$application = new Application();
// required to use BufferedOutput()
$application->setAutoExit(false);
// composer package list, formatted as json, will be barfed into $output
$status = $application->run($input, $output);
if($status === 0) {
// grab the output from the $output buffer
$json = $output->fetch();
// decode the json string into an object
$list = json_decode($json);
// Profit!
print_r($list);
}
?>
The output will be something like this:
stdClass Object
(
[installed] => Array
(
... omitted ...
[91] => stdClass Object
(
[name] => drupal/core
[version] => 8.9.12
[description] => Drupal is an open source content management platform powering millions of websites and applications.
)
... omitted ...
)
)
With the help of Onema's hint Google found the rest of the solution for me here.
Upvotes: 1
Reputation: 933
I understand it's old post and above answers solves the problem with a bit of digging. In Symfony2.7, I had a bit issue making it work, so with above suggestions, I dug a little and have compiled the full answer here. Hope it will be useful for someone.
Using Console command under console command
Upvotes: 0
Reputation: 7582
There is an new Output class (as of v2.4.0) called BufferedOutput
.
This is a very simple class that will return and clear the buffered output when the method fetch
is called:
$output = new BufferedOutput();
$input = new ArrayInput($arguments);
$code = $command->run($input, $output);
if($code == 0) {
$outputText = $output->fetch();
echo $outputText;
}
Upvotes: 12
Reputation: 778
I did the following
use Symfony\Component\Console\Input\ArrayInput;
use Symfony\Component\Console\Output\StreamOutput;
$tmpFile = tmpfile();
$output = new StreamOutput($tmpFile);
$input = new ArrayInput(array(
'parameter' => 'value',
));
$command = . . .
$command->run($input, $output);
fseek($tmpFile, 0);
$output = fread($tmpFile, 1024);
fclose($tmpFile);
echo $output;
¡it works!
Upvotes: 3
Reputation: 422
you have to pass the command in the arguments array, and to avoid the confirmation dialog in doctrine:fixtures:load you have to pass --append and not --force
$arguments = array(
'command' => 'doctrine:fixtures:load',
//'--append' => true
''
);
or it will fail with error message “Not enough arguments.”
Upvotes: 22
Reputation: 22756
Here you can have a basic command inside a command. The output from the second command can be a json, then you just have to decode the output json to retrieve your array.
$command = $this->getApplication()->find('doctrine:fixtures:load');
$arguments = array(
//'--force' => true
''
);
$input = new ArrayInput($arguments);
$returnCode = $command->run($input, $output);
if($returnCode != 0) {
$text .= 'fixtures successfully loaded ...';
$output = json_decode(rtrim($output));
}
Upvotes: 26