CODEWITHSUNDEEP
xmlxslt
Wondering
Wondering

Reputation: 5076

How to dynamically get value attribute value of a row using XSLT

I have to create one table using XSLT and CSS. The table should look like

                ID    FNAME
                 1    AA
                 2    BB

XML:

<students>
    <studentDetails  id="1" fname="AA"/>
    <studentDetails  id="2" fname="BB"/>
</students>

XSLT so far: I have traverse upto studentDetails and then

<td >
      <xsl:call-template name="zz">
      <xsl:with-param name="child-name" select="'id'"/>
      </xsl:call-template>
    </td>
     <xsl:template name="zz">
<xsl:param name="child-name"/>

<xsl:value-of select="*[name(@id) = $child-name]"/>//should print 1 and then 2 in next row

Can somebody suggest where i am going wrong?

Upvotes: 1

Views: 3098

Answers (2)

Michael Krelin - hacker
Michael Krelin - hacker

Reputation: 143081

try

<xsl:value-of select="attribute::*[name() = $child-name]"/>

instead.

Edit: I have just read through Dewfy's answer. This is equivalent to what he proposed. Except for his "at first" part is an alternative to this, not something you have to in addition to changing xsl:value-of.

Upvotes: 2

Dewfy
Dewfy

Reputation: 23624

At first don't pass "'id'" just use "id" At second = pattern * selects node, but you need attr (@*), so you need write:

<xsl:value-of select="@*[name()=$child-name]"/>

Upvotes: 5

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