Reputation: 26281
Below is how I previously verified dates. I also had my own functions to convert date formats, however, now am using PHP's DateTime class so no longer need them. How should I best verify a valid date using DataTime? Please also let me know whether you think I should be using DataTime in the first place. Thanks
PS. I am using Object oriented style, and not Procedural style.
static public function verifyDate($date)
{
//Given m/d/Y and returns date if valid, else NULL.
$d=explode('/',$date);
return ((isset($d[0])&&isset($d[1])&&isset($d[2]))?(checkdate($d[0],$d[1],$d[2])?$date:NULL):NULL);
}
Upvotes: 27
Views: 76802
Reputation: 51
For me, the combination of date_parse and checkdate works best and it is almost one-liner:
$date="2024-02-29";
$dp=date_parse("$date");
if (sprintf("%04d-%02d-%02d",$dp['year'], $dp['month'], $dp['day'])===$date && checkdate($dp['month'], $dp['day'], $dp['year'])) {
// format is OK and date is valid
}
Upvotes: 0
Reputation: 7
With the following an empty string like '' or 0 or '0000-00-00 00:00:00' is false
$valid = strtotime($date) > 0;
Upvotes: -1
Reputation: 98
I needed to allow user input in (n) different, known, formats...including microtime. Here is an example with 3.
function validateDate($date)
{
$formats = ['Y-m-d','Y-m-d H:i:s','Y-m-d H:i:s.u'];
foreach($formats as $format) {
$d = DateTime::createFromFormat($format, $date);
if ($d && $d->format($format) == $date) return true;
}
return false;
}
Upvotes: 1
Reputation: 165
$date[] = '20/11/2569';
$date[] = 'lksdjflskdj';
$date[] = '11/21/1973 10:20:30';
$date[] = '21/11/1973 10:20:30';
$date[] = " ' or uid like '%admin%";
foreach($date as $dt)echo date('Y-m-d H:i:s', strtotime($dt))."\n";
Output
1970-01-01 05:30:00
1970-01-01 05:30:00
1970-01-01 05:30:00
1973-11-21 10:20:30
1970-01-01 05:30:00
1970-01-01 05:30:00
Upvotes: 0
Reputation: 1217
With DateTime you can make the shortest date&time validator for all formats.
function validateDate($date, $format = 'Y-m-d H:i:s')
{
$d = DateTime::createFromFormat($format, $date);
return $d && $d->format($format) == $date;
}
var_dump(validateDate('2012-02-28 12:12:12')); # true
var_dump(validateDate('2012-02-30 12:12:12')); # false
function was copied from this answer or php.net
Upvotes: 17
Reputation: 12665
You can try this one:
static public function verifyDate($date)
{
return (DateTime::createFromFormat('m/d/Y', $date) !== false);
}
This outputs true/false. You could return DateTime
object directly:
static public function verifyDate($date)
{
return DateTime::createFromFormat('m/d/Y', $date);
}
Then you get back a DateTime
object or false on failure.
UPDATE:
Thanks to Elvis Ciotti who showed that createFromFormat accepts invalid dates like 45/45/2014. More information on that: https://stackoverflow.com/a/10120725/1948627
I've extended the method with a strict check option:
static public function verifyDate($date, $strict = true)
{
$dateTime = DateTime::createFromFormat('m/d/Y', $date);
if ($strict) {
$errors = DateTime::getLastErrors();
if (!empty($errors['warning_count'])) {
return false;
}
}
return $dateTime !== false;
}
Upvotes: 80
Reputation: 395
Try this:
function is_valid_date($date,$format='dmY')
{
$f = DateTime::createFromFormat($format, $date);
$valid = DateTime::getLastErrors();
return ($valid['warning_count']==0 and $valid['error_count']==0);
}
Upvotes: 6
Reputation: 16055
You could check this resource: http://php.net/manual/en/datetime.getlasterrors.php
The PHP codes states:
try {
$date = new DateTime('asdfasdf');
} catch (Exception $e) {
print_r(DateTime::getLastErrors());
// or
echo $e->getMessage();
}
Upvotes: 11