CODEWITHSUNDEEP
phphtmlcodeigniter
prakashchhetri
prakashchhetri

Reputation: 1816

Dropdown in codeigniter using array as values

I have returned a result_array() in $categories variable and now I want to create a dropdown menu. But if I directly use the variable, all the elements of the array are going to be displayed. However I just want to display the name and keep its id as value. How do i do it?

$options = $categories;
echo form_dropdown('category', $options);

I want something like

<select name="category">
<option value="1"> ABC </option>
..... 
<option value="10"> NNNC </option>
</select>

Upvotes: 0

Views: 9329

Answers (4)

Vijayan Jayaraman
Vijayan Jayaraman

Reputation: 21

$options = array_combine(
    array_column($categories, 'id'),
    array_column($categories, 'value')
);
echo form_dropdown('category', $options, '', array('class' => 'form-control'));

Upvotes: 0

prakashchhetri
prakashchhetri

Reputation: 1816

well since I was getting all the returned rows as array in $categories

Hence a print_r() on $categories gave me the output 

Array
(
    [0] => Array
        (
            [id] => 24
            [name] => First
        )

    [1] => Array
        (
            [id] => 25
            [name] => Second
        )

    [2] => Array
        (
            [id] => 26
            [name] => third
        )

)

But I needed something like the code below to make the dropdown work

Array
(
    [24] => First
    [25] => Second
    [26] => third
)

SO I had do modify my code as below 

$options = array();
                    foreach ($categories as $category) {
                        $options[$category['id']] =  $category['name'];
                    }

                    echo form_dropdown('cat_id', $options);

Hence the HTML generated was as follows which was the markup I desired.

<select name="category">
<option value="24"> First </option>
<option value="25"> Second </option>
<option value="26"> Third </option>
</select>

And it did worked . Thanks for the answers, But after two days of head scratching, I finally did it. Sometimes it is so difficult when u are a beginner.

Upvotes: 1

Nikola Ninkovic
Nikola Ninkovic

Reputation: 1262

Keys in your $options array are not actual ID's of database rows.

So your $options array looks like this:

Array(
'0' => array('id'=>'10', 'value'=>'someval1'),
'1' => array('id'=>'22', 'value'=>'someval2'),
'2' => array('id'=>'36', 'value'=>'someval3'))

To see this, put print_r($options); before echo call.

To make real dropdown you should make helper function that looks like this:

function my_form_dropdown($name, $result_array){
    $options = array();
    foreach ($result_array as $key => $value){
        $options[$value['id']] = $value['value'];
    }
    return form_dropdown($name, $options);
}

Upvotes: 5

tomexsans
tomexsans

Reputation: 4527

you can do

$options = array(


    '1' => 'ABC',
    '2' => 'NNC'
);

echo form_dropdown('category', $options);

where the key will be the value of the dropdown

Upvotes: 0

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