CODEWITHSUNDEEP
jqueryjquery-animate
user1492776
user1492776

Reputation: 280

How to repeat a function call in jQuery

I have this code:

<script type="text/javascript" src="http://code.jquery.com/jquery-1.4.3.min.js"></script>
<script type="text/javascript">
    $(document).ready(function() { 
        function loop(){
            $('#picOne').fadeIn(0).fadeOut(8000);
            $('#picTwo').delay(2000).fadeIn(6000).fadeOut(5000);
            $('#picTree').delay(10000).fadeIn(2000).fadeOut(16000);
            $('#picFour').delay(12000).fadeIn(16000).fadeOut(5000);
        }
        loop();
    });
</script>

But when the last pic fades out, the code doesn't repeat. What is the problem?

Upvotes: 1

Views: 33453

Answers (4)

Shubham Verma
Shubham Verma

Reputation: 178

setInterval only except function try this

function loop(){
        $('#picOne').fadeIn(0).fadeOut(8000);
        $('#picTwo').delay(2000).fadeIn(6000).fadeOut(5000);
        $('#picTree').delay(10000).fadeIn(2000).fadeOut(16000);
        $('#picFour').delay(12000).fadeIn(16000).fadeOut(5000);
}
setInterval(loop, 5000);

Upvotes: 1

user2631532
user2631532

Reputation: 1

I would like to say that this function does work well, and whomever did it, did a great job. I edited the demo and it works well with pictures.

<div id="picOne">
 <img id="picOne" src="http://www.phphq.net/demos/phAlbum/album/Windows%20Wallpapers/Missing/Waterfall.jpg"/></div>
<div id="picTwo">
<img id="picTwo" src="http://newevolutiondesigns.com/images/freebies/colorful-background-21.jpg"/></div>
<div id="picTree">
 <img id="picTree" src="http://www.phphq.net/demos/phAlbum/album/Windows%20Wallpapers/Missing/Waterfall.jpg"/></div>
  <div id="picFour">
<img id="picFour" src="http://www.photoinpixel.com/mypicture/amazing-background-wallpapers.jpg"/></div>

Function

var $elements = $('#picOne, #picTwo, #picTree, #picFour');

function anim_loop(index) {
    $elements.eq(index).fadeIn(1000, function() {
        var $self = $(this);
        setTimeout(function() {
            $self.fadeOut(1000);
            anim_loop((index + 1) % $elements.length);
        }, 3000);
    }); }

anim_loop(0); // start with the first element

Upvotes: 0

Felix Kling
Felix Kling

Reputation: 816404

Assuming you want to duration of the animation being the same for each element:

var $elements = $('#picOne, #picTwo, #picTree, #picFour');

function anim_loop(index) {
    // Get the element with that index and do the animation
    $elements.eq(index).fadeIn(1000).delay(3000).fadeOut(1000, function() { 
        // Kind of recursive call, increasing the index and keeping in the
        // the range of valid indexes
        anim_loop((index + 1) % $elements.length);
    });
}

anim_loop(0); // start with the first element

I don't know exactly how the animation should be, but I hope it makes the concept clear.

Update: To simultaneously fade out and in an image after a certain time period, use setTimeout and call fadeOut and anim_loop in the callback:

$elements.eq(index).fadeIn(1000, function() {
    var $self = $(this);
    setTimeout(function() {
        $self.fadeOut(1000);
        anim_loop((index + 1) % $elements.length);
    }, 3000);
});

DEMO

Upvotes: 7

Mateusz Rogulski
Mateusz Rogulski

Reputation: 7445

There are no problem couse your function is called only once.

If you want to looped them you can use setInterval() or setTimeout()

setInterval(function(){loop()}, 16000);

function loop(){
     $('#picOne').fadeIn(0).fadeOut(8000);
     $('#picTwo').delay(2000).fadeIn(6000).fadeOut(5000);
     $('#picTree').delay(10000).fadeIn(2000).fadeOut(16000);
     $('#picFour').delay(12000).fadeIn(16000).fadeOut(5000);

}

or

function loop(){
     $('#picOne').fadeIn(0).fadeOut(8000);
     $('#picTwo').delay(2000).fadeIn(6000).fadeOut(5000);
     $('#picTree').delay(10000).fadeIn(2000).fadeOut(16000);
     $('#picFour').delay(12000).fadeIn(16000).fadeOut(5000);
 setTimeout(function(){loop()}, 16000);
}

In both cases function will be called every 16 seconds = 16000 miliseconds.

Upvotes: 0

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