CODEWITHSUNDEEP
pythonprintingpython-2.7
user2014142
user2014142

Reputation: 31

script prints out of order

I am using Python 2.7.3 and trying to understand why this script executes print statements out of order. i.e. the "-" prints AFTER the 2nd for loop.

My script:

def cheeseshop(kind, *arguments, **keywords):
    print "-- Do you have any", kind, "?"
    print "-- I'm sorry, we're all out of", kind
    for arg in arguments:
        print arg
    print "-" * 40
    keys = sorted(keywords.keys())
    for kw in keys:
        print kw, ":", keywords[kw]

cheeseshop("Limburger", "It's very runny, sir.",
           "It's really very, VERY runny, sir.",
           {'shopkeeper':'Michael Palin',
           'client':"John Cleese",
           'sketch':"Cheese Shop Sketch"})

The output:

-- Do you have any Limburger ?
-- I'm sorry, we're all out of Limburger
It's very runny, sir.
It's really very, VERY runny, sir.
{'shopkeeper': 'Michael Palin', 'sketch': 'Cheese Shop Sketch', 'client': 'John Cleese'}
----------------------------------------

Why print "-"*40 execute BEFORE the dictionary as would be expected?

Upvotes: 3

Views: 931

Answers (1)

Martijn Pieters
Martijn Pieters

Reputation: 1121864

You didn't pass in the dictionary as keywords. Use the ** syntax to do so:

cheeseshop("Limburger", "It's very runny, sir.",
           "It's really very, VERY runny, sir.",
           **{'shopkeeper':'Michael Palin',
           'client':"John Cleese",
           'sketch':"Cheese Shop Sketch"})

or don't use a dictionary at all:

cheeseshop("Limburger", "It's very runny, sir.",
           "It's really very, VERY runny, sir.",
           shopkeeper='Michael Palin',
           client="John Cleese",
           sketch="Cheese Shop Sketch")

Upvotes: 8

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