CODEWITHSUNDEEP
djangodjango-urls
Hervé
Hervé

Reputation: 139

got an unexpected keyword argument url

I have this error since 2 days

TypeError at /manager/produit/detail/s/

produit_detail() got an unexpected keyword argument 'letter'

and I don't see the bug, can you help me?

This is my urls.py:

url(r'^manager/produit/detail/(?P<letter>\w{1})/$',
    'appli.views.produit_detail', name="produit_detail"),

this is views.py

def produit_detail(request,letter):

    from appli.models import Produit
    
    produits = Produit.objetcs.filter(nom__startswith=letter)

    return render(request,'produit_detail.html')

i called the url from this template

<p>{% for i in l %}
                <a href="{% url 'produit_detail' i %}">{{ i }}</a>
             {% endfor %}</p>

Upvotes: 0

Views: 3066

Answers (1)

catherine
catherine

Reputation: 22808

You can only put i if you put int value. If you want to call a string you must put the variable with the value like this.

<p>{% for i in l %}
       Sample 1: <a href="{% url produit_detail letter=i %}">{{ i }}</a>
       Sample 2: <a href="{% url appli:produit_detail letter=i %}">{{ i }}</a>
       Sample 3: <a href="/manager/produit/detail/{{i}}">{{ i }}</a>
   {% endfor %}
</p>You did not put value for letter

Upvotes: 1

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