CODEWITHSUNDEEP
iphonexcodecall
gabrjan
gabrjan

Reputation: 3049

Why my code won't work on iphone 5

So i make an application that calls an number:

NSString *cleanedString = [[number componentsSeparatedByCharactersInSet:[[NSCharacterSet characterSetWithCharactersInString:@"0123456789-+()"] invertedSet]] componentsJoinedByString:@""];
NSString *escapedPhoneNumber = [cleanedString stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *telURL = [NSURL URLWithString:[NSString stringWithFormat:@"tel://%@", escapedPhoneNumber]];
UIWebView *mCallWebview = [[UIWebView alloc] init]  ;
[self.view addSubview:mCallWebview];
[mCallWebview loadRequest:[NSURLRequest requestWithURL:telURL]];

However a tester with iPhone 5 reported that it's not working on his phone while on main works fine. He doesn't get any crashes or anything.

Thank u!

Upvotes: 0

Views: 558

Answers (3)

skyline
skyline

Reputation: 183

you can check this code.i hope this will help you. 

NSString *phoneNo = @"your phone no";
NSString *strAppend  = [@"tel:" stringByAppendingString:phoneNo];
[[UIApplication sharedApplication]
  openURL:[NSURL URLWithString:strAppend]];

Upvotes: 0

Irshad Mansuri
Irshad Mansuri

Reputation: 407

  NSString *number = YOUR-NUMBER;       
  NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"telprompt:%@",number]];

  [[UIApplication sharedApplication] openURL:url];

Try with this code, it will navigate back to your app after finished call

Upvotes: 2

rckoenes
rckoenes

Reputation: 69499

The tel: URL schema is used incorrectly in your code, remove the //

NSURL *telURL = [NSURL URLWithString:[NSString stringWithFormat:@"tel:%@", escapedPhoneNumber]];

Upvotes: 1

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