CODEWITHSUNDEEP
sqlmysql
halocursed
halocursed

Reputation: 2495

Help in a Join query

SELECT game_ratingstblx245v.game_id,avg( game_ratingstblx245v.rating ) 
         as avg_rating,
       count(DISTINCT game_ratingstblx245v.userid) 
          as count,
       game_data.name,
       game_data.id ,
       avg(game_ratings.critic_rating),count(DISTINCT game_ratings.critic) 
         as cr_count
FROM game_data 
LEFT JOIN game_ratingstblx245v ON game_ratingstblx245v.game_id = game_data.id 
LEFT JOIN game_ratings         ON game_ratings.game_id = game_data.id 
WHERE game_data.release_date < NOW() 
GROUP BY game_ratingstblx245v.game_id 
ORDER BY game_data.release_date DESC,
         game_data.name


I am currenty using this query to extract values from 3 tables
game_data - id(foreign key), name, release_date \games info
game_ratings - game_id(foreign key),critic , rating \critic rating
game_ratingstblx245v - game_id(foreign key), rating, userid \user rating


What I want to do with this query is select all id's from table game_data order by release_date descending, then check the avg rating from table game_ratings and game_ratingsblx245v corresponding to individual id's(if games have not been rated the result should return null from fields of the latter two tables)..Now the problem I am facing here is the result is not coming out as expected(some games which have not been rated are showing up while others are not), can you guys check my query and tell me where am i wrong if so...Thanks

Upvotes: 1

Views: 72

Answers (1)

Bill Karwin
Bill Karwin

Reputation: 562981

You shouldn't use the game_ratingstblx245v.game_id column in your GROUP BY, since it could be NULL when there are no ratings for a given game id. Use game_data.id instead.

Here's how I would write the query:

SELECT g.id, g.name,
       AVG( x.rating ) AS avg_user_rating,
       COUNT( DISTINCT x.userid ) AS user_count,
       AVG( r.critic_rating ) AS avg_critic_rating, 
       COUNT( DISTINCT r.critic ) AS critic_count
FROM game_data g
LEFT JOIN game_ratingstblx245v x ON (x.game_id = g.id)
LEFT JOIN game_ratings r         ON (r.game_id = g.id)
WHERE g.release_date < NOW() 
GROUP BY g.id 
ORDER BY g.release_date DESC, g.name;

Note that although this query produces a Cartesian product between x and r, it doesn't affect the calculation of the average ratings. Just be aware in the future that if you were doing SUM() or COUNT(), the calculations could be exaggerated by an unintended Cartesian product.

Upvotes: 2

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