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mysqlsqlselectjoin
Abhinav Joshi
Abhinav Joshi

Reputation: 101

Error in acessing results in a relational database

i have a table setup as the folowing

enter image description here

I am trying to write one query to return the result where status=1 confirmed =1 and user ID=specified. I want the result to dispay the user id , the name associated to that user id, the freind id and the name associated to that freind id. So far following tutorials on the web i have come up with the following query

SELECT `freinds.User ID`, `freinds.Freind ID`, `users.User`, `users.User` FROM `freinds` WHERE `User ID`= 6 INNER JOIN `users` on `users.ID`=6 AND `users.ID`=`freinds.Freind ID`

However i am getting an sql error with this query. I think what i am supposed to do is Inner join the user table twice but i am not exactly sure as to how to do it

Upvotes: 3

Views: 74

Answers (1)

John Woo
John Woo

Reputation: 263853

the problem is you have wrap the tablename and columnname with backtick as a whole. you need to separate it, or if the name is not on `MySQL Reserved Keywords, remove the backticks.

You also need to join the table User twice so you can get the names for each ID on table Freinds.

SELECT  a.`User ID`, 
        a.`Freind ID`, 
        b.User FriendName,
        c.User UserName
FROM    `freinds` a
        INNER JOIN `users` b 
            ON b.ID = a.`Freind ID`
        INNER JOIN users c
            ON c.id = a.`user ID`
WHERE   `User ID`= 6

As a sidenote, if one of the ID is nullable, LEFT JOIN is preferred than INNER JOIN.

To fully gain knowledge about joins, kindly visit the link below:

Upvotes: 2

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