CODEWITHSUNDEEP
c#visual-studio-2008
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Reputation: 95

Keep getting errors on a basic c# console app

I've trying to learn c# but keep coming across a problem. Essentially, I'm trying to learn how to create a class that does some function and is called to perform that function by the application.

the error I have ended up with (there have been loads of others but I've tried to play around to 'fix' them) is

is a 'type' but is used like a variable

the code I've put together so far is;

    namespace FirstConsoleApplication
    {

        class Program
        {
            public class checkConvertValue
            {
                public string formula1(string x)
                {
                    Int32 isnumber = 0;
                    bool canConvert = Int32.TryParse(x, out isnumber);
                    string returnValue;
                    if (canConvert == true)
                    {
                        int val3 = Int32.Parse(x);
                        switch (val3)
                        {
                            case 50:
                                returnValue = "yep its 50";
                                break;
                            case 51:
                                returnValue = "hmmm.... its 51... what are you gonna do about that??";
                                break;
                            case 52:
                                returnValue = "lets not get sloppy now...";
                                break;
                            default:
                                returnValue = "nope, its definately something else";
                                break;
                        };
                    }
                    else
                    {
                        returnValue = "Thats not a number";
                    };
                        return returnValue;
                }
            }
           static void Main(string[] args)
            {
                string num;
                string result1;
                do
                {
                    Console.WriteLine("Guess what the value is, hint... its integer and between 1 and 100");

                    num = Console.ReadLine();
                    result1 = checkConvertValue(num);
                    Console.WriteLine(result1);

                } while (result1 != "yep its 50");
                Console.ReadLine();
            }
        }

}

can someone let me know where I'm going wrong?

Upvotes: 0

Views: 119

Answers (5)

Jens
Jens

Reputation: 477

You are trying to call the class checkConvertValue as if it were a method. To actually call the method you need to call the formula1 method from an instance of class checkConvert value. Try this:

num = Console.ReadLine();
checkConvertValue classReference = new checkConvertValue();
result1 = classReference.formula1(num);
Console.WriteLine(result1);

Upvotes: 1

John Woo
John Woo

Reputation: 263733

object checkConvertValue is a class but you are using it as a method.

you need to declare an instance of it before you can use the method formula1

num = Console.ReadLine();
checkConvertValue chkVal = new checkConvertValue();
result1 = checkConvertValue.formula1(num);
Console.WriteLine(result1);

Upvotes: 0

nrsharma
nrsharma

Reputation: 2562

You are trying to access the function by class name, which is wrong. You have to do like this

result1 = new checkConvertValue().formula1(num);

Upvotes: 0

DGibbs
DGibbs

Reputation: 14618

There are a couple things wrong here.

  • checkConvertValue doesn't contain a constructor which takes num (assuming its a string), i think you meant to call formula(...)

  • You need to create an instance of checkConvertValue and then call the formula method from that or make the class and method static and call it like checkConvertValue.formula1 etc...

Upvotes: 0

Marc Gravell
Marc Gravell

Reputation: 1062885

You presumably mean:

result1 = new checkConvertValue().formula1(num);

or if you make it (formula1) a static method:

result1 = checkConvertValue.formula1(num);

btw; there's no point in parsing x twice; if the TryParse succeeds, the integer value is stored in isnumber.

Upvotes: 1

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