CODEWITHSUNDEEP
javaregex
A_M
A_M

Reputation: 7851

excluding matching characters in regular expression

I'm stuck with a regular expression problem.

I've got a string which I need to match. The string always starts with 2 letters, and then is followed by a 6 digit number, e.g.

However, there is one combination of letters which I need to ignore. e.g.:

So I want to write a regular expression to match only the normal format of the strings.

At the moment, I'm having to do:

Pattern pattern = Pattern.compile("[A-Z]{2}[0-9]{6}");
...

if(pattern.matcher(n).matches() && !n.toUpperCase().startsWith("XX")) {
    // do match stuff
}

How can I rewrite my regexp so that I can get rid of the startsWith clause in my code above?

Upvotes: 1

Views: 366

Answers (1)

Blixt
Blixt

Reputation: 50197

Use a negative look-ahead:

"(?!XX)[A-Z]{2}[0-9]{6}"

(?!XX) means "don't match if I can match XX at the current position", but it doesn't actually change the current position (so the two characters it tested can still be matched by [A-Z]{2}.)

Upvotes: 4

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