CODEWITHSUNDEEP
phpjavascript
user1914374
user1914374

Reputation: 1260

How to get line of code to accept single quote

Because of a single quote I am receiving a expecting ) after argument list error:

window.top.stopAudioUpload(1, '43', 'Thorne, Grandma's Goodbye excerpt.m4a');

audioupload.php (line 11, col 54)

My question is how can I get the line of code to accept single quote?

Code:

 <script language="javascript" type="text/javascript">
 window.top.stopAudioUpload(<?php echo $result; ?>, '<?php echo $id; ?>', '<?php echo $_FILES['fileAudio']['name'] ?>');
 </script>

Upvotes: 0

Views: 143

Answers (4)

earl3s
earl3s

Reputation: 2373

Your issue lies here:

window.top.stopAudioUpload(<?php echo $result; ?>, '<?php echo $id; ?>', '<?php echo $_FILES['fileAudio']['name'] ?>');

Changing the single quotes around'<?php echo will fix it. So:

window.top.stopAudioUpload("<?php echo $result; ?>", "<?php echo $id; ?>", "<?php echo $_FILES['fileAudio']['name'] ?>");

You can also use json_encode($_FILES['fileAudio']['name']). This adds quotes automatically.

Upvotes: 0

Wolfman Joe
Wolfman Joe

Reputation: 799

You could try to manually escape your single-quote with a backslash Thorn, Grandma\'s Goodbye excerpt.m4a or you could use the escape function - see the docs here:

http://www.php.net/manual/en/function.htmlspecialchars.php

Upvotes: 0

Niet the Dark Absol
Niet the Dark Absol

Reputation: 324790

Try this:

<script type="text/javascript">
top.stopAudioUpload(
  <?php echo json_encode($result); ?>,
  <?php echo json_encode($id); ?>,
  <?php echo json_encode($_FILES['fileAudio']['name']); ?>
);
</script>

Note the lack of quotes - this is important, because json_encode will add these automatically if needed.

Upvotes: 5

Antonio Papa
Antonio Papa

Reputation: 1666

Try \ escape character 'Thorne, Grandma\'s Goodbye excerpt.m4a'

Upvotes: 2

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