Reputation: 65951
How can I create a dictionary with no duplicate values from a dictionary that may have duplicate values?
IDictionary<string, string> myDict = new Dictionary<string, string>();
myDict.Add("1", "blue");
myDict.Add("2", "blue");
myDict.Add("3", "red");
myDict.Add("4", "green");
uniqueValueDict = myDict.???
Edit:
-I don't care which key is kept. - Is there something using Distinct() operation?
Upvotes: 22
Views: 36855
Reputation: 1
Just a footnote to those using the Revit API, this is one method that works for me in removing duplicate elements, when you can't use say wallType as your object type and instead need to leverage raw elements. it's a beaut mate.
//Add Pair.value to known values HashSet
HashSet<string> knownValues = new HashSet<string>();
Dictionary<Wall, string> uniqueValues = new Dictionary<Wall, string>();
foreach (var pair in wall_Dict)
{
if (knownValues.Add(pair.Value))
{
uniqueValues.Add(pair.Key, pair.Value);
}
}
Upvotes: 0
Reputation: 649
This is how I did it:
dictionary.add(control, "string1");
dictionary.add(control, "string1");
dictionary.add(control, "string2");
int x = 0;
for (int i = 0; i < dictionary.Count; i++)
{
if (dictionary.ElementAt(i).Value == valu)
{
x++;
}
if (x > 1)
{
dictionary.Remove(control);
}
}
Upvotes: 1
Reputation: 1081
In addition to the answer of Jon Skeet , if your value is an intern object you can use :
var uniqueValues = myDict.GroupBy(pair => pair.Value.Property)
.Select(group => group.First())
.ToDictionary(pair => pair.Key, pair => pair.Value);
This way you will remove the duplicate only on one property of the object
Upvotes: 0
Reputation: 59655
The brute-force solution would be something like the following
var result = dictionary
.GroupBy(kvp => kvp.Value)
.ToDictionary(grp => grp.First().Value, grp.Key)
assuming you don't really care about the key used to represent a group of duplicates and it is acceptable to rebuild the dictionary.
Upvotes: 9
Reputation: 1500635
What do you want to do with the duplicates? If you don't mind which key you lose, just build another dictionary like this:
IDictionary<string, string> myDict = new Dictionary<string, string>();
myDict.Add("1", "blue");
myDict.Add("2", "blue");
myDict.Add("3", "red");
myDict.Add("4", "green");
HashSet<string> knownValues = new HashSet<string>();
Dictionary<string, string> uniqueValues = new Dictionary<string, string>();
foreach (var pair in myDict)
{
if (knownValues.Add(pair.Value))
{
uniqueValues.Add(pair.Key, pair.Value);
}
}
That assumes you're using .NET 3.5, admittedly. Let me know if you need a .NET 2.0 solution.
Here's a LINQ-based solution which I find pleasantly compact...
var uniqueValues = myDict.GroupBy(pair => pair.Value)
.Select(group => group.First())
.ToDictionary(pair => pair.Key, pair => pair.Value);
Upvotes: 51
Reputation: 15785
Jon beat me to the .NET 3.5 solution, but this should work if you need a .NET 2.0 solution:
List<string> vals = new List<string>();
Dictionary<string, string> newDict = new Dictionary<string, string>();
foreach (KeyValuePair<string, string> item in myDict)
{
if (!vals.Contains(item.Value))
{
newDict.Add(item.Key, item.Value);
vals.Add(item.Value);
}
}
Upvotes: 3
Reputation: 851
Dictionary<string, string> test = new Dictionary<string,string>();
test.Add("1", "blue");
test.Add("2", "blue");
test.Add("3", "green");
test.Add("4", "red");
Dictionary<string, string> test2 = new Dictionary<string, string>();
foreach (KeyValuePair<string, string> entry in test)
{
if (!test2.ContainsValue(entry.Value))
test2.Add(entry.Key, entry.Value);
}
Upvotes: 1
Reputation: 15511
foreach (var key in mydict.Keys)
tempdict[mydict[key]] = key;
foreach (var value in tempdict.Keys)
uniquedict[tempdict[value]] = value;
Upvotes: 1