CODEWITHSUNDEEP
cheader-filesc-preprocessor
Alex
Alex

Reputation: 44305

What does '_IO(...)' mean in C headers in Linux?

I have a Linux standard header file e.g.

/usr/src/linux-headers-3.2.0-35/include/linux/usbdevice_fs.h

which contain define statements as follows:

#define USBDEVFS_SUBMITURB32       _IOR('U', 10, struct usbdevfs_urb32)
#define USBDEVFS_DISCARDURB        _IO('U', 11)
#define USBDEVFS_REAPURB           _IOW('U', 12, void *)

What does '_IOR', '_IO' and '_IOW' mean? What value is actually given e.g. to USBDEVFS_DISCARDURB?

Upvotes: 11

Views: 11149

Answers (2)

werewindle
werewindle

Reputation: 3029

They define ioctl numbers, based on ioctl function and input parameters. The are defined in kernel, in include/asm-generic/ioctl.h.

You need to include <linux/ioctl.h> (or linux/asm-generic/ioctl.h) in your program. Before including
/usr/src/linux-headers-3.2.0-35/include/linux/usbdevice_fs.h

You can't "precompile" this values (e.g. USBDEVFS_DISCARDURB), because they can be different on other platforms. For example, you are developing your code on plain old x86, but then someone will try to use it on x86_64/arm/mips/etc. So you should always include kernel's ioctl.h to make sure, you are using right values.

Upvotes: 9

Eregrith
Eregrith

Reputation: 4366

These are also macros defined elsewhere.

In general if you want to see your code after pre-processor has been computed use

gcc -E foo.c

this will output your code pre-processed

For example:

foo.c

#define FORTY_TWO 42

int main(void)
{
  int foo = FORTY_TWO;
}

will give you with gcc -E foo.c:

int main(void)
{
  int foo = 42;
}

Upvotes: 1

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