CODEWITHSUNDEEP
javascriptregex
Shane
Shane

Reputation: 5151

How to substitute a variable in a regex

I have a function that pulls out special modifiers from a string passed to a function

function parseContext(record, txtInput) {
    var context = String((txtInput.match(/(^\@[\w\n]*)/g) || [""])[0]).replace("@", "");
    record.entry = txtInput;
    if (command && command.length) {
        txtInput = String(txtInput).replace("/" + command, "");
        record.command = command;
        record.entry = txtInput;
    }
    return record;
}

What I'm not sure how to do (in this case), is how to abstract it so I can parse out an arbitrary leading character in the form of something like:

function parseModifier(record, modifier, txtInput) {
    var command = String((txtInput.match(/(^\  ---what goes here? --- [\w\n]*)/g) || [""])[0]).replace(modifier, "");

Is this possible?

Upvotes: 0

Views: 212

Answers (1)

Florian Margaine
Florian Margaine

Reputation: 60717

var re = new RegExp('(^\\' + anyVariable + '[\w\n]*)', 'g');
var command = String((txtInput.match(re || [""])[0]).replace(modifier, "");

Using the RegExp constructor allows you to use any variable, since it takes a string as input.

Upvotes: 4

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