CODEWITHSUNDEEP
linuxbashshell
user2027303
user2027303

Reputation: 707

How to put the output of command in bash variable

I want to put the output of command in bash variable and then further use that variable in other command

Suppose i want something like this

ls | $(variable) |awk '/$variable/{print "here"}'

Upvotes: 2

Views: 12513

Answers (4)

Hui Zheng
Hui Zheng

Reputation: 10224

You can try:

variable=$(ls); awk "/$variable/"'{print "here"}'

Note 1: /$variable/ is surrounded by double quotes, otherwise it won't be replaced by output of command.

Note 2: The above command may fail since the output of ls may contains "/" or newline, which will break the awk command. You may change ls to something like ls | tr '\n' ' ' | tr -d '/' | sed 's/ *$//g'(replace all newlines with spaces; delete all slashes; remove the trailing whitespace), depending on your goal.

Note 3: to avoid variable assignment polluting the current shell's environment, you can wrap the above command by parentheses, i.e. (variable=$(some_command); awk "/$variable/"'{print "here"}')

Upvotes: 0

Oliver
Oliver

Reputation: 31

Or

now=`date`

Back ticks

Which is easier for me since it works in any shell or perl

Upvotes: 0

Elalfer
Elalfer

Reputation: 5338

To put command output into variable you can use following format in bash

variable=`pwd`
echo $variable

Upvotes: 2

Carl Norum
Carl Norum

Reputation: 224844

I don't know that you can easily do it in a single step like that, but I don't know why you'd pipe it to awk and use it in the script like that anyway. Here's the two step version, but I'm not really sure what it does:

variable=$(ls)
echo ${variable} | awk "/${variable}/{printf \"here\"}"

Upvotes: 0

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