CODEWITHSUNDEEP
androidstringsplit
RajaReddy PolamReddy
RajaReddy PolamReddy

Reputation: 22493

How to split this String?

I want to split this string 

String info = "0.542008835 meters height from ground";

from this i want to get only two decimals like this 0.54.

by using this i am getting that

String[] _new = rhs.split("(?<=\\G....)");

But i am facing problem here, if string does't contain any decimals like this string

String info = "1 meters height from ground";

for this string i am getting those characters upto first 4 in the split string like 1 me. i want only numbers to split if it has decimals, How to solve this problem.

Upvotes: 2

Views: 404

Answers (5)

Arnold
Arnold

Reputation: 273

This will work when you know the String near the numbers, with int and double numbers as well.

    String a ="0.542008835 meters height from ground";
    String b = a.replace(" meters height from ground", "");
    int c = (int) ((Double.parseDouble(b))*100);
    double d = ((double)c/100);

Upvotes: 1

Kingamajick
Kingamajick

Reputation: 2281

You could use a regex to do this as an alternative to Deepzz's method, this will handle the case where there is a '.' in the later part of the String, I've included an example below. It's not clear from your question is you actually want to remaining part of the String, but you could add a second group to the reg ex to capture this.

public static void main(String[] args) {
    final String test1 = "1.23 foo";
    final String test2 = "1 foo";
    final String test3 = "1.234 foo";
    final String test4 = "1.234 fo.o";
    final String test5 = "1 fo.o";
    getStartingDecimal(test1);
    getStartingDecimal(test2);
    getStartingDecimal(test3);
    getStartingDecimal(test4);
    getStartingDecimal(test5);

}

private static void getStartingDecimal(final String s) {
    System.out.print(s + " : ");
    Pattern pattern = Pattern.compile("^(\\d+\\.\\d\\d)");
    Matcher matcher = pattern.matcher(s);
    if(matcher.find()) {
        System.out.println(matcher.group(1));
    } else {
        System.out.println("Doesn't start with decimal");
    }
}

Upvotes: 2

Paul
Paul

Reputation: 5223

Assuming the number is always the first part of the string:

String numStr = rhs.split(" ")[0];
Double num = Double.parseDouble(numStr);

After that you can use the String Formatter to get the desired representation of the number.

Upvotes: 1

Chintan Khetiya
Chintan Khetiya

Reputation: 16142

I think you can check by white space after first value. see this If you get the space then get first character only.

For checking if a string contains whitespace use a Matcher and call it's find method.

Pattern pattern = Pattern.compile("\\s");
Matcher matcher = pattern.matcher(s);
boolean found = matcher.find();

If you want to check if it only consists of whitespace then you can use String.matches:

boolean isWhitespace = s.matches("^\\s*$");

Upvotes: 3

Deepzz
Deepzz

Reputation: 4571

if(info.contains("."))
{
       String[] _new = rhs.split("(?<=\\G....)");
}

Upvotes: 7

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