CODEWITHSUNDEEP
pythondjangomodel-view-controller
Deepankar Bajpeyi
Deepankar Bajpeyi

Reputation: 5889

Django : saving form to database

So I have the following model :

class Recipe(models.Model):
        title = models.CharField(max_length=100)
        ingredients = models.TextField(max_length=200,help_text="Put the ingredients required for the recepies here !")
        instructions = models.TextField(max_length=500)

        posted_on = models.DateTimeField('Posted On')

        def __unicode__(self):
                return self.title

Now what I want to do is that I have a front-end in html called add.html which has a form like: 

<!DOCTYPE html>


<head><title>New Recipe</title></head>
<body>
<h1>Add A new Recipe Here</h1>

<form action="/recipes/add/" method="post">
{% csrf_token  %}

<label>ID<label>
<input type="number" name="id"></input><br />

<label>Title </label>
<input type ="text" name="title"><br />

<label>Ingredients</label>
<input type="text" name="ingredients" />
<br />

<label>Instructions </label>
<input type="text" name="instructions" />
...

Here is how I am saving the form using ModelForm: 

def add(request):
        if request.method == 'POST':
                form = RecipeForm(request.POST)
                if form.is_valid():

                        form.save()
                        #redirect
                        return HttpResponse("Thank you")
                else:
                        return HttpResponse("Form Not Valid")
        else:
                form = RecipeForm()

                context = Context({'form':form,})
                context.update(csrf(request))
                template = loader.get_template('myApp/add.html')
                return HttpResponse(template.render(context))

When I run this I always get "form Invalid" So now my problem is, Should the html form add.html have the EXACT mappings as my model Recipe ?
If yes ,then

  1. How do I add the corresponding types in the html form (for posted_on) ?
  2. How do I handle the id that is implicitly created by syncdb?
  3. Is there any alternative ?

I have just started to learn Django

Upvotes: 3

Views: 15186

Answers (2)

Nick
Nick

Reputation: 474

1) Change posted_on to automatically add the date posted.

posted_on = models.DateTimeField(auto_now_add=True)

2) Django will handle the pk id creation for you.

3) Why not use a ModelForm for this? Documentation. 

class RecipeForm(ModelForm):
    class Meta:
        model = Recipe

You can either use exclude or include on fields to make sure your form only contains the fields from Recipe that you want to include in your form.

Upvotes: 4

catherine
catherine

Reputation: 22808

models.py

class Recipe(models.Model):
    title = models.CharField(max_length=100)
    ingredients = models.TextField(max_length=200,help_text="Put the ingredients required for the recepies here !")
    instructions = models.TextField(max_length=500)

    posted_on = models.DateTimeField(auto_add_now=True)

    def __unicode__(self):
            return self.title

page.html 

<!DOCTYPE html>

<head><title>New Recipe</title></head>
<body>
<h1>Add A new Recipe Here</h1>

<form action="/recipes/add/" method="post">
{% csrf_token  %}
     {% form.as_p %}
     <input type="submit" value="submit">
</form>
</body>
</html>

views.py

from django.contrib import messages
from django.core.urlresolvers import reverse
from django.http import HttpResponseRedirect
from django.shortcuts import render

def add(request):
    if request.method == 'POST':
            form = RecipeForm(request.POST)
            if form.is_valid():
                form.save()
                    return HttpResponseRedirect(reverse('app_name:url'))
            else:
                messages.error(request, "Error")
    return render(request, 'myApp/add.html', {'form': RecipeForm()})

Upvotes: 2

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