Reputation: 719
I am trying to understand recursion in Scheme and I have a hard time doing the dry run for it, for example a simple Fibonacci number problem.
Could someone break down the steps in which the additions take place, for me?
(define (fib n)
(if (<= n 2)
1
(+ (fib (- n 1)) (fib (- n 2)))))
Upvotes: 8
Views: 28405
Reputation: 19705
If you're using Racket, as your tags indicate, then you have a built-in stepper.
Enter the program into DrRacket, and click Step in the top-right menu:
Then a stepper window will open up. Click Step over and over, and you can walk through the execution of the program.
If you want the number of steps to be a bit more manageable, pick a number lower than 10 for the execution to trace.
Upvotes: 8
Reputation: 71065
In pseudocode, fib(n) = n <= 2 -> 1 ; else -> fib(n-1) + fib(n-2)
=> (1 1 2 3 5 ...).
For example, fib(5)
is reduced as:
fib(5)
fib(4) + fib(3)
(fib(3) + fib(2)) + fib(3)
((fib(2) + fib(1)) + fib(2)) + fib(3)
((1 + 1) + fib(2)) + fib(3)
(2 + fib(2)) + fib(3)
(2 + 1) + fib(3)
3 + fib(3)
3 + (fib(2) + fib(1))
3 + (1 + 1)
3 + 2
5
Upvotes: 4
Reputation: 25
This is a code that prints the fibonacci sequence members from 1 to n each in a new line. Importnat to note, it's using two very simple helper functions. Hope this helps.
;Prints to the screen all the member up to the nth member in the fibonaci sequence (define (fibo n)
(let ((i 1))
(if (= n 1)
(display 1)
(fiboHelp i n))))
;Helper function that presents Fibonaci sequence from bottom index i until upper index n
(define (fiboHelp i n)
(if (= i n)
(display(fiboMember i))
(begin
(display (fiboMember i))
(newline)
(fiboHelp (+ i 1)n))))
;Returns the nth member of the Fibonaci sequence
(define (fiboMember n)
(if (<= n 2)
(+ 1 0)
(+ (fiboMember(- n 1))(fiboMember(- n 2)))))
Upvotes: -1