CODEWITHSUNDEEP
stringbatch-filesubstitution
ingroxd
ingroxd

Reputation: 1025

BATCH: String substitution sub

I'm trying to make a sub in batch that find a string in a string and replace it with a third one. Searching around, I found here that I can erase a string with the SET command.

So, here's what I tried:

:modifyString what with [in]
SET _what=%~1
ECHO "%_what%"
SET "_with=%~2
ECHO "%toWith%"
SET _In=%~3
ECHO "%_In%"
SET _In=%_In:%toWhat%=%toWith%%
ECHO %_In%
SET "%~3=%_In%"
EXIT /B

The ECHOs are there only for "debugging" purposes.

What I know is that the error is in...

SET _In=%_In:%toWhat%=%toWith%%

...because of the % character that close the %_in% variable.

I tried also things such as...

SET _In=%_In:!toWhat!=!toWith!%
SET _In=!_In:%toWhat%=%toWith%!

...and others without sense.

This is the main problem, the other is to return %_In% in [in].

Any tips?

Upvotes: 2

Views: 716

Answers (2)

ingroxd
ingroxd

Reputation: 1025

Thank you all guys!

I paste you what I finally made:

:modifyString what with in tRtn
set "_in=%~3"
set "_in=!_in:%~1=%~2!"
IF NOT "%~4" == "" SET %~4=%_in%
EXIT /B

E.G. If I call this sub in this way:

SET "str=All your base are belong to us"
SET "toFind=your base are belong"
SET "space=of your bases belong"
ECHO %str%
CALL :modifyString "%toFind%" "%space%" "%str%" string

%string% would became the new corrected string, so if you do...

ECHO "%string%"

it would print:

"All of your bases belong to us"

P.S. I'm sorry if I'm late, but because of my low reputation i had to wait!

Upvotes: 2

David Ruhmann
David Ruhmann

Reputation: 11367

Here is an example using the ! DelayedExpansion method.

@echo off
setlocal EnableExtensions EnableDelayedExpansion
set "xxString=All your base are belong to us"
set "xxSubString=your base are belong"
set "xxNewSubString=of your bases belong"
echo Before
set xx
echo.
set "xxString=!xxString:%xxSubString%=%xxNewSubString%!"
echo After
set xx
endlocal
pause >nul

Output

Before
xxNewSubString=of your bases belong
xxString=All your base are belong to us
xxSubString=your base are belong

After
xxNewSubString=of your bases belong
xxString=All of your bases belong to us
xxSubString=your base are belong

Fixed Yours

@echo off
:: Make sure that you have delayed expansion enabled.
setlocal EnableDelayedExpansion

:modifyString what with [in]
SET "_what=%~1"
SET "_with=%~2"
SET "_In=%~3"
ECHO "%_what%"
ECHO "%_with%"
ECHO "%_In%"
:: The variable names were not the same as the ones
:: defined above.
SET _In=!_In:%_what%=%_with%!
ECHO %_In%

:: This will not change the value of the 3rd parameter
:: but instead will create a new parameter with the
:: value of %3 as the variable name.
SET "%~3=%_In%"
endlocal
EXIT /B

How to do the substring replacement without delayed expansion. Use the call command to create two levels of variable expansion. Use single % around variables to expand first and double %% around variables to expand second.

@echo off
setlocal EnableExtensions
set "xxString=All your base are belong to us"
set "xxSubString=your base are belong"
set "xxNewSubString=of your bases belong"
echo Before
set xx
echo.
call set "xxString=%%xxString:%xxSubString%=%xxNewSubString%%%"
echo After
set xx
endlocal
pause >nul

Upvotes: 4

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