CODEWITHSUNDEEP
javascriptjqueryfilterfindjquery-filter
user962206
user962206

Reputation: 16117

JQuery AJax Getting Page Fragments Find vs Filter

Here's the the form the Ajax code I am testing.

$('body').on('submit','#sign-in', function(e) {
    e.preventDefault();

    var data = $(this).serialize();

    var url = $(this).attr('action');
    $.ajax({
        //this is the php file that processes the data and send mail
        url : url,
        type : "POST",
        data : data,
        dataType:"html",
        //Do not cache the page
        cache : false,
        //success
        success : function(response,status) {
            console.log($(response).filter('#dashboard'));
            console.log($(response).find('#dashboard').html());
        }
    });
});

Here is the response.

<!DOCTYPE html>
<%@ taglib prefix="s" uri="/struts-tags"%>
<html>
<body>
    <div id = "dashboard">
        <div id = "dash2">
        <h1>HELLO</h1>
        </div>
    </div>
</body>
</html>

Based from the code above upon, success jQuery filter was able to fetch the div with an id #dashboard however find return me an undefined.

Why is it working like that?

For your information, I am using JQuery 1.9

UPDATE

Using the suggestion of Bergi, I have removed the html,body and head tag of the returned html and this is the error I received.

Uncaught Error: Syntax error, unrecognized expression:

HELLO

HELLO FITCCHHH jquery-1.9.0.min.js:2

Upvotes: 2

Views: 3546

Answers (3)

Adam
Adam

Reputation: 6733

You should use parseHTML as indicated above. The difference between filter and find appears to be where the element is in the returned HTML snippet. If you are looking for #foo then use .filter('#foo') if #foo is a top-level element in the returned HTML and .find('#foo') otherwise.

Upvotes: 1

George Filippakos
George Filippakos

Reputation: 16569

If you are using jquery 1.9 , you should no-longer parse html like so:

var html = $(response);

Instead you should be using the following:

var html = $.parseHTML(response);
html = $(html).find('#dashboard').html();

From Jquery Docs 1.9: HTML strings passed to jQuery() that start with something other than a less-than character will be interpreted as a selector. Since the string usually cannot be interpreted as a selector, the most likely result will be an "invalid selector syntax" error thrown by the Sizzle selector engine. Use jQuery.parseHTML() to parse arbitrary HTML.

Upvotes: 3

Bergi
Bergi

Reputation: 664346

jQuery sets your whole page as the innerHTML of a <div>, and therefore doctype, html, head and body elements are not parsed. You only get back a collection of the resulting elements, and since your #dashboard is one of these top-level elements you need to filter instead of find.

See also:

I'm not sure how to solve this, apparently there's much jQuery quirks around there. What I can think of:

  • try jQuery.parseXML
  • rely on filter getting the element in question out of the jQuery collection. Though, since browsers seem not to be consistent about what the parse you should do something like $response[$response.is("#dashboard") ? "filter" : "find"]("#dashboard")
  • Append the malformed collection to some element and find from there: $("<div/>").html(response).find("#dashboard")
  • wait for jQuery.parseHTML
  • do not send a whole HTML document, but only the #dashboard element you're interested in as a html string

Upvotes: 4

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