CODEWITHSUNDEEP
javaphpandroidjson
TheLettuceMaster
TheLettuceMaster

Reputation: 15734

Getting Null from JSON Data encoded in PHP, outputting to Java

My JSON output in PHP is done this way:

 print json_encode(array('rate' => $topcat, 'hometown' => $hometown, 'talk' => $talk));

My JSON output looks like this in my browser:

{"rate":"Movies","hometown":"Seattle, WA","talk":"Movies"}

in Java/Android I do this:

protected void onPostExecute(Void v) {

    try {
        JSONArray jArray = new JSONArray(result);
        JSONObject json_data = null;
        for (int i = 0; i < jArray.length(); i++) {
            json_data = jArray.getJSONObject(i);


            Hometown = json_data.getString("hometown");
            FavCategory = json_data.getString("rate");              
            Talk = json_data.getString("talk");



        }
    } catch (JSONException e1) {

    } catch (ParseException e1) {
        e1.printStackTrace();
    }

    if (Hometown.equals("")) {
        Hometown = "Not Specified";
    }

    tvHometown.setText(Hometown);
    tvRate.setText(FavCategory);
    tvTalk.setText(Talk);

    Log.d("Log: ", Hometown + " " + FavCategory + " " + Talk);

}

}

On that Log, I get this: Seattle, WA, null, null

Can anyone see why?

EDIT: New Java Code, still getting error:

String homeTown = "", favCategory = "", favTalk = "";
        try {
            JSONObject jsonData = new JSONObject(result);

            homeTown = jsonData.getString("hometown");
            favCategory = jsonData.getString("rate");
            favTalk = jsonData.getString("talk");


            tvHometown.setText(homeTown);
            tvRate.setText(favCategory);
            tvTalk.setText(favTalk);




} catch (JSONException e1) {

    } catch (ParseException e1) {
        e1.printStackTrace();
    }

I am getting an exception:

02-05 08:51:48.078: E/log_tag(22958): Error in http connection org.json.JSONException: Value null of type org.json.JSONObject$1 cannot be converted to JSONArray

Upvotes: 0

Views: 235

Answers (2)

DevfaR
DevfaR

Reputation: 1616

you should have a square bracket to indicate that it is a JSONArray your result is in JSONObject if you want to get the data of each JSONArray your result should be more like this 

{"rate": ["samplevalue","samplevalue"],"Movies" : ["samplevalue","samplevalue"],"hometown":["Seattle, WA"],"talk":["Movies"]}

Upvotes: 0

Matt Ball
Matt Ball

Reputation: 359966

Despite the PHP vocabulary, the top-level element of this JSON:

{"rate":"Movies","hometown":"Seattle, WA","talk":"Movies"}

is an object (a key-value mapping), not an array. The {}s are a dead giveaway.

Change this

JSONArray jArray = new JSONArray(result);

to this:

JSONObject jsonData = new JSONObject(result);

and go from there:

String hometown = jsonData.getString("hometown");
String favCategory = jsonData.getString("rate");              
String talk = jsonData.getString("talk");

Note how, as a matter of good Java style, I use lowerCamelCased variable names.

Upvotes: 4

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