CODEWITHSUNDEEP
c#asp.netdrop-down-menufor-loop
wikinevis
wikinevis

Reputation: 189

Making drop down list in ASP.Net by foreach loop

we can make dropdown list in asp.net component with below syntax

 <asp:DropDownList ID="test" runat="server">
      <asp:ListItem Text="1" Value="1"></asp:ListItem>
 </asp:DropDownList>

if we want our combo box contain 1 to 1000 , is there any way to populate it with foreach loop , rather than manually add 1000 item to it ?

Upvotes: 3

Views: 20634

Answers (6)

markp3rry
markp3rry

Reputation: 734

Here's some pseudocode:

for (int i = 0; i < 1000; i++)
{
    ListItem item = new ListItem();
    item.Text = i.ToString();
    test.Items.Add(item);
}

You will have to find out exactly how to create the ListItem and populate it with a value.

Upvotes: 0

MTAdmin
MTAdmin

Reputation: 1033

Sure, in your code-behind: 

if (!Page.IsPostBack)
{
    // Populate DropDownList
    for (int i = 1; i < 1001; i++)
    {
        ListItem li = new ListItem(i.ToString(),i.ToString());
        test.Items.Add(li);
    }
}

Upvotes: 1

freefaller
freefaller

Reputation: 19953

Very basic code...

if(!Page.IsPostBack)
{
  for (int i = 1; i <= 1000; i++)
  {
    test.Items.Add(new ListItem(i.ToString(), i.ToString()));
  }
}

Upvotes: 0

Jeremy Wiggins
Jeremy Wiggins

Reputation: 7299

How about just binding the dropdown list directly to a collection of numbers?

IEnumerable<int> numbers = Enumerable.Range(1, 1000);
test.DataSource = numbers;
test.DataBind();

Upvotes: 1

शेखर
शेखर

Reputation: 17614

 for( int i=1;i<=100;i++)
 {
    ListItem li=new ListIem(i.ToString(),i.ToString());
    test.Items.add(li);
 }

Upvotes: 0

Tim Schmelter
Tim Schmelter

Reputation: 460168

Yes, you can add ListItems programmatically:

for(int i=1; i<=1000; i++)
{
    ListItem item = new ListItem(i.ToString(), i.ToString());
    test.Items.Add(item);
}

ListItemCollection.Add

You could also use this linq query and use it as DataSource:

var source = Enumerable.Range(1, 1000)
    .Select(i => new { Text= i.ToString(), Value=i.ToString() });
test.DataSource = source;
test.DataTextField = "Text";
test.DataValueField = "Value";
test.DataBind();

Upvotes: 5

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