CODEWITHSUNDEEP
phparrays
Daniel Robinson
Daniel Robinson

Reputation: 653

show only values in my second array php

I have two arrays which I am comparing. The comparison is working perfectly as follows:

  $tmp = array_diff_key($arr1, $arr2);
  $echo $tmp;

However, I only want to display the values that exist in array 2 that don't exist in array 1.

Edit: Ok so thank for everyone's help. How ever I am still unable to make it work.

I am now using

   $tmp = array_diff($arr2, $arr1);
  var_dump($tmp);

which prints out the following:

  array(1) { [0]=> array(3) { [0]=> string(4) "cars" [1]=> string(4) "vans" [2]=> string(6) "people" } }

So, I'll explain a little.

Array 1 has cars, vans (this is pulled from the database).

Array 2 has cars, people (this is entered from a form).

I'm trying to only show values that are not in the database so I thought $tmp would echo just people as cars is in the database and vans is in $arr1

I hope thats clear as its even confusing me writing it ;)

If I var_dump both array individually I get

    array(3) { [0]=> NULL [1]=> string(4) "cars" [2]=> string(4) "vans" } array(1) { [0]=> array(2) { [0]=> string(6) "people" [1]=> string(5) "tanks" } }

Upvotes: 1

Views: 492

Answers (6)

Achrome
Achrome

Reputation: 7821

Use array_intersect. array_intersect gives values which are in both.

$tmp2 = array_intersect($arr1, $arr2);
var_dump($tmp2);

Edit : Misread the question. array_diff will serve the purpose. array_diff returns values from argument1 which are not present in the rest of the arguments.

$tmp2 = array_diff($arr2, $arr1);
var_dump($tmp2);

Edit : In your case, your $arr2 has an array inside it which has the values. So, you will need to array_diff($arr2[0], $arr1);

Here's a working fiddle.

Upvotes: 2

Mike Brant
Mike Brant

Reputation: 71384

If you are concerned with values and not key values, then you should just use array_diff(). You would also need to reverse the order of the arrays in the parameters. Finally echoing an array isn't going to show you what you want, use var_dump(). So putting it all together:

$tmp = array_diff($arr2, $arr1);
var_dump($tmp);

Upvotes: 1

CEPA
CEPA

Reputation: 2602

swap the direction:

$tmp = array_diff_key($arr2, $arr1);
  $echo $tmp;

Upvotes: 1

MikeB
MikeB

Reputation: 2452

From my understanding of array_diff_key, the function returns an array containing all the entries from argument1 whose keys are not present in any of the other arrays. So just put $arr2 into the first argument.

So your code should be:

$tmp = array_diff_key($arr2, $arr1);
$echo $tmp;

Source

Upvotes: 1

Philippe Boissonneault
Philippe Boissonneault

Reputation: 3949

you can do as follows : 

foreach($tmp as $key=>$value) {
    if(isset($arr2[$key])) {
        echo $arr2[$key];
    }
}

Upvotes: 1

Explosion Pills
Explosion Pills

Reputation: 191729

$tmp = array_diff_key($arr2, $arr1);
$echo $tmp;

echo $tmp will just output 'Array' I think, so you probably have to loop over it (perhaps with foreach) to display each individual value, or use var_dump.

array_diff_key also works with keys, array_diff with values (you mention "values" in your question).

Upvotes: 2

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